[英]Byte slice manipulation
I'm writing a program that should parse and reply to network packets but I'm a bit annoyed because I can't do simple C style return (int)buffer[at];
我正在编写一个程序,该程序应该解析并回复网络数据包,但由于无法执行简单的C样式
return (int)buffer[at];
我有点恼火return (int)buffer[at];
with an array of bytes. 与字节数组。 Is there any better way to retrieve 4 bytes from byte[] as int32 than the following?
有没有比以下更好的方法从byte []作为int32检索4个字节了?
func (packet *Packet) GetInt32(at int) int32 {
return int32(packet.buffer[at]) << 24 +
int32(packet.buffer[at+1]) << 16 +
int32(packet.buffer[at+2]) << 8 +
int32(packet.buffer[at+3])
}
It works correctly but I was thinking if there was a better way to do this. 它可以正常工作,但是我在想是否有更好的方法可以做到这一点。
package main
import (
"encoding/binary"
"fmt"
"math"
)
type Packet struct {
buffer []byte
}
func (p *Packet) Int32(i int) int32 {
return int32(binary.BigEndian.Uint32(p.buffer[i : i+4]))
}
func (p *Packet) Float32(i int) float32 {
return math.Float32frombits(binary.BigEndian.Uint32(p.buffer[i : i+4]))
}
func main() {
p := &Packet{buffer: []byte{0x01, 0x02, 0x00, 0x00, 0xFF, 0xFF, 0x07}}
fmt.Println(p.Int32(2), p.Float32(2))
}
Output: 65535 9.1834e-41
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