C ++ —此语句的含义是什么？

Question

I saw the following class definition and cannot figure out the meaning of the line 1.

class Noisy {
public:
  Noisy() throw();
 ~Noisy() throw();
  Noisy& operator= (const Noisy&) throw();
  Noisy            (const Noisy&) throw(); // Line 1
};

What is the meaning of this line and what is the usage of this line?

Thank you

Answer 1

It isn't a statement. It is a declaration of a copy constructor that is specified as throwing no exceptions.

You can find out more in your favorite good introductory C++ book .

Answer 2

Look at this thread. It will give you some more insight. Should I use an exception specifier in C++?