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Where子句中的未知列

[英]Unknown Column in Where Clause

Why MySQL claims of not finding a column? 为什么MySQL声称找不到列? I did specify it in 'select clause'. 我确实在'select子句'中指定了它。

MySQL 5.1.39 MySQL 5.1.39

Error Code: 1054 Unknown column ' dt' in 'where clause' 错误代码: 1054'where子句'中的未知列' dt '

Query: 查询:

-- Generate a Table for Every Day in 2008 Year
SELECT DATE_ADD('2008-01-01',
            INTERVAL (ones.num + tens.num + hundreds.num) DAY) dt
FROM
    (SELECT 0 num UNION ALL
     SELECT 1 num UNION ALL
     SELECT 2 num UNION ALL
     SELECT 3 num UNION ALL
     SELECT 4 num UNION ALL
     SELECT 5 num UNION ALL
     SELECT 6 num UNION ALL
     SELECT 7 num UNION ALL
     SELECT 8 num UNION ALL
     SELECT 9 num) ones
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 10 num UNION ALL
     SELECT 20 num UNION ALL
     SELECT 30 num UNION ALL
     SELECT 40 num UNION ALL
     SELECT 50 num UNION ALL
     SELECT 60 num UNION ALL
     SELECT 70 num UNION ALL
     SELECT 80 num UNION ALL
     SELECT 90 num) tens
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 100 num UNION ALL
     SELECT 200 num UNION ALL
     SELECT 300 num) hundreds
WHERE YEAR(dt) < 2009
ORDER BY dt;

You must reference column aliases in a HAVING clause. 您必须在HAVING子句中引用列别名。 HAVING conditions are executed on the results set after the query has been processed, as opposed to WHERE clauses which are part of the intial query execution. 在处理查询之后,在结果集上执行HAVING条件,而不是作为初始查询执行的一部分的WHERE子句。 Because of this HAVING is able to operate on column aliases which are only available in the results set. 因此, HAVING能够对列别名进行操作,这些列别名仅在结果集中可用。

-- Generate a Table for Every Day in 2008 Year
SELECT DATE_ADD('2008-01-01',
            INTERVAL (ones.num + tens.num + hundreds.num) DAY) dt
FROM
    (SELECT 0 num UNION ALL
     SELECT 1 num UNION ALL
     SELECT 2 num UNION ALL
     SELECT 3 num UNION ALL
     SELECT 4 num UNION ALL
     SELECT 5 num UNION ALL
     SELECT 6 num UNION ALL
     SELECT 7 num UNION ALL
     SELECT 8 num UNION ALL
     SELECT 9 num) ones
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 10 num UNION ALL
     SELECT 20 num UNION ALL
     SELECT 30 num UNION ALL
     SELECT 40 num UNION ALL
     SELECT 50 num UNION ALL
     SELECT 60 num UNION ALL
     SELECT 70 num UNION ALL
     SELECT 80 num UNION ALL
     SELECT 90 num) tens
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 100 num UNION ALL
     SELECT 200 num UNION ALL
     SELECT 300 num) hundreds
HAVING YEAR(dt) < 2009
ORDER BY dt;

Having without a group by is mysql-specific. 没有group by是特定于mysql的。 You could also try something like this: 你也可以尝试这样的事情:

select * from (
SELECT DATE_ADD('2008-01-01',
      INTERVAL (ones.num + tens.num + hundreds.num) DAY) dt
FROM
    (SELECT 0 num UNION ALL
     SELECT 1 num UNION ALL
     SELECT 2 num UNION ALL
     SELECT 3 num UNION ALL
     SELECT 4 num UNION ALL
     SELECT 5 num UNION ALL
     SELECT 6 num UNION ALL
     SELECT 7 num UNION ALL
     SELECT 8 num UNION ALL
     SELECT 9 num) ones
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 10 num UNION ALL
     SELECT 20 num UNION ALL
     SELECT 30 num UNION ALL
     SELECT 40 num UNION ALL
     SELECT 50 num UNION ALL
     SELECT 60 num UNION ALL
     SELECT 70 num UNION ALL
     SELECT 80 num UNION ALL
     SELECT 90 num) tens
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 100 num UNION ALL
     SELECT 200 num UNION ALL
     SELECT 300 num) hundreds
dates
where year(dates.dt) < 2009 
ORDER BY dt;

It can be a bit tricky using those named columns, but you can use 'HAVING' instead of WHERE: 使用这些命名列可能有点棘手,但您可以使用'HAVING'而不是WHERE:

SELECT DATE_ADD('2008-01-01',
      INTERVAL (ones.num + tens.num + hundreds.num) DAY) dt
FROM
    (SELECT 0 num UNION ALL
     SELECT 1 num UNION ALL
     SELECT 2 num UNION ALL
     SELECT 3 num UNION ALL
     SELECT 4 num UNION ALL
     SELECT 5 num UNION ALL
     SELECT 6 num UNION ALL
     SELECT 7 num UNION ALL
     SELECT 8 num UNION ALL
     SELECT 9 num) ones
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 10 num UNION ALL
     SELECT 20 num UNION ALL
     SELECT 30 num UNION ALL
     SELECT 40 num UNION ALL
     SELECT 50 num UNION ALL
     SELECT 60 num UNION ALL
     SELECT 70 num UNION ALL
     SELECT 80 num UNION ALL
     SELECT 90 num) tens
CROSS JOIN
    (SELECT 0 num UNION ALL
     SELECT 100 num UNION ALL
     SELECT 200 num UNION ALL
     SELECT 300 num) hundreds
HAVING YEAR(dt) < 2009
ORDER BY dt;

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