如何将元组中的一组列表中的第一个值相加？

Question

Hey, I would like to be able to perform this but with being selective for which lists I sum up. Let's say, that same example, but with only adding up the first number from the 3rd and 4th list.

Answer 1

Something like:

sum(int(tuple_list[i][0]) for i in range(3,5))

range(x, y) generates a list of integers from x(included) to y(excluded) and 1 as the step. If you want to change the range(x, y, step) will do the same but increasing by step.

You can find the official documentation here

Or you can do:

sum(float(close[4]) for close in tickers[30:40])

Answer 2

>>> l1
[(0, 2), (1, 3), (2, 4), (3, 5), (4, 6), (5, 7), (6, 8), (7, 9), (8, 10), (9, 11)]
>>> sum([el[0] for (nr, el) in enumerate(l1) if nr in [3, 4]])
7
>>> 

Answer 3

If you want to limit by some property of each element, you can use filter() before feeding it to the code posted in your link. This will let you write a unique filter depending on what you want. This doesn't work for the example you gave, but it seemed like you were more interested in the general case.

sum(pair[0] for pair in filter(PREDICATE_FUNCTION_OR_LAMBDA, list_of_pairs))

Answer 4

not seen an answer using reduce yet.

reduce(lambda sumSoFar,(tuple0,tuple1): sumSoFar+tuple0, list, 0)

In essence sum is identical to reduce(int.__add__, list, 0)

edit: didn't read the predicate part.

Easily fixed, but probably not the best answer anymore:

predicate = lambda x: x == 2 or x == 4
reduce(lambda sumSoFar,(t0,t1): sumSoFar+(t0 if predicate(t0) else 0), list, 0)