Ruby Regex Gsub何时不匹配

Question

I want to gsub all characters in a string that are not letters and replace with '#'. I think I need a regular expression that goes something like, "gsub() when this regex does not match."

Any ideas?

Answer 1

看马，没有正则表达式......

str.tr( '^A-Za-z', '#' )

Answer 2

str.gsub(/[^a-zA-Z]/, '#')

^表示不匹配

Answer 3

当然，你可以使用字符类否定：

"aBc$%^".gsub(/[^A-Za-z]/, '#') => "aBc###"

Answer 4

在Codepad上试试这个 ：

puts "kjhdfuy37685682#$$%@dfjahf".gsub(/[^a-z]/i, '#')

Answer 5

Words do count

all character s ... replace with '#' str.gsub(/[^a-zA-Z]+/, '#')

each character ... replace with '#' str.gsub(/[^a-zA-Z]/, '#')