完成xslt新手。如何在xslt 1.0版中合并这2个xml源。应用分组和排序？

Question

The Transformation source 转化源

Data1.xml 数据1.xml

 <DEALERSHIP reg_number="01234567">
 <MANUFACTURER name="VAUXHALL">
     <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20060331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
    <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20040331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
     <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>2.5</CAR_ENG>
        <CAR_MODEL>CALIBRA</CAR_MODEL>
        <CAR_REG_DATE>20030331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>BLUE</COLOUR>
    </CAR>
</MANUFACTURER>
<MANUFACTURER name="FORD">
     <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>2.5</CAR_ENG>
        <CAR_MODEL>CMAX</CAR_MODEL>
        <CAR_REG_DATE>20050331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
    </MANUFACTURER>

The external data Data2.xml 外部数据Data2.xml

<DEALERSHIP reg_number="01234567">
<MANUFACTURER name="VAUXHALL">
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20060331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>BLUE</COLOUR>
    </CAR>
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20060331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>BLUE</COLOUR>
    </CAR>
</MANUFACTURER>
<MANUFACTURER name="TOYOTA">
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>Corolla</CAR_MODEL>
        <CAR_REG_DATE>20030812</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
</MANUFACTURER>

required output 所需的输出

<DEALERSHIP reg_number="01234567">
<MANUFACTURER name="VAUXHALL">
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20060331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>BLUE</COLOUR>
    </CAR>
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20060331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
    <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>ASTRA</CAR_MODEL>
        <CAR_REG_DATE>20040331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
    <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>2.5</CAR_ENG>
        <CAR_MODEL>CALIBRA</CAR_MODEL>
        <CAR_REG_DATE>20030331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>BLUE</COLOUR>
    </CAR>

</MANUFACTURER>
<MANUFACTURER name="FORD">
    <CAR>
        <CAR_VIN>12345678901234567</CAR_VIN>
        <CAR_ENG>2.5</CAR_ENG>
        <CAR_MODEL>CMAX</CAR_MODEL>
        <CAR_REG_DATE>20050331</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>HH54 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
</MANUFACTURER>
<MANUFACTURER name="TOYOTA">
    <CAR>
        <CAR_VIN>XXX12345678901234567</CAR_VIN>
        <CAR_ENG>1.9</CAR_ENG>
        <CAR_MODEL>Corolla</CAR_MODEL>
        <CAR_REG_DATE>20030812</CAR_REG_DATE>
        <TRANSMISSION>A</TRANSMISSION>
        <CAR_REG>SS00 RRY</CAR_REG>
        <COLOUR>RED</COLOUR>
    </CAR>
</MANUFACTURER>

My first attempt xsl 我第一次尝试xsl

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0" xmlns:externalSupplier="externalSupplier://uk.co.skyline.XslConnector"
xmlns:consol="consol://uk.co.skyline.Xslconsolidated"
exclude-result-prefixes="externalSupplier consol">

<xsl:output method="xml" />



<!-- *** Parameters *** -->
<!-- ****************** -->
<xsl:param name="dealerNo"></xsl:param>  <!-- ** dealer Reg No being processed -->
<xsl:param name="supplier"></xsl:param> 
<xsl:param name="cust"></xsl:param>          


<!-- Load xml from external into variables -->
<!-- ************************************* -->
<!--
    <xsl:variable name="externalStuff" select="externalSupplier:getData(
    $dealerNo,  $supplier, $cust)"></xsl:variable>
-->

<xsl:variable name="externalStuff" 
select="document('Data2.xml')/*"></xsl:variable>



<xsl:template match="/">


    <xsl:for-each select="DEALERSHIP">

        <xsl:variable name="RegNum" select="@reg_number" />

        <xsl:element name="{name()}">
            <xsl:apply-templates select="." mode="copyAttributes" />

            <xsl:for-each select="MANUFACTURER">
                <xsl:variable name="manName" select="@name" />
                <xsl:apply-templates select=".">

                    <xsl:with-param name="externalMan"
                        select="$externalStuff[@reg_number = 
                        $RegNum]/MANUFACTURER[@name = $manName]" />
                </xsl:apply-templates>
            </xsl:for-each>
        </xsl:element>

    </xsl:for-each>

</xsl:template>

<!-- Process the MANUFACTURER elements -->
<!-- **************************** -->
<xsl:template match="MANUFACTURER">
    <xsl:param name="externalMan" />

    <!-- Get the reg number of the dealer -->
    <xsl:variable name="regNum" select="../@reg_number" />

    <!-- Get the manufacturer name -->
    <xsl:variable name="eManName" select="@name" />

    <xsl:element name="{name()}">
        <xsl:apply-templates select="." mode="copyAttributes" />

        <xsl:variable name="cars" select="CAR" />


        <xsl:apply-templates
            select="CAR | $externalMan/CAR[not (CAR_REG_DATE = 
            $cars/CAR_REG_DATE and CAR_MODEL = $cars/CAR_MODEL ) ]">

            <xsl:sort select="CAR_REG_DATE" data-type="number" 
            order="descending" />
            <xsl:sort select="CAR_MODEL" data-type="number" 
            order="descending" />
        </xsl:apply-templates>

    </xsl:element>

</xsl:template>


<!-- Process the CAR elements -->
<!-- **************************** -->
<xsl:template match="CAR">
    <xsl:param name="externalMan" />

    <xsl:choose>


        <xsl:when test="CAR_VIN">
            <xsl:copy-of select="." />
        </xsl:when>
        <xsl:otherwise>


            <xsl:if
                test="string-length(CAR_REG_DATE) = 8">

                <CAR>
                    <xsl:copy-of select="*" />
                    <CAR_VIN>
                        <xsl:value-of
                            select="consol:getConSol(../../@reg_number, 
                            CAR_REG_DATE, CAR_MODEL)" />
                    </CAR_VIN>
                </CAR>

            </xsl:if>

        </xsl:otherwise>
    </xsl:choose>
</xsl:template>




<!-- Copy the element's attributes to the output -->
<!-- ******************************************* -->
<xsl:template match="DEALERSHIP | MANUFACTURER" mode="copyAttributes">

    <xsl:for-each select="attribute::*">
        <xsl:attribute name="{name()}"><xsl:value-of select="." />
        </xsl:attribute>
    </xsl:for-each>
</xsl:template>

This transformation happens server side initiated through java. 这种转换发生在通过Java启动的服务器端。

As you can see from the stylesheet I have to include the Data2.xml through a call to some java processing. 从样式表中可以看到，我必须通过对某些Java处理的调用来包含Data2.xml。 I have used the document() for debug purposes. 我已将document（）用于调试目的。

I managed to get the calls from/to the java inputs working and the main structure of the xslt output working. 我设法从/到Java输入工作和xslt输出的主要结构的调用。 Where a CAR_VIN is not present in any data the call to java happens on transform of every CAR element. 在任何数据中都不存在CAR_VIN的情况下，对java的调用发生在每个CAR元素的转换上。 The given data includes all CAR_VIN's to avoid call outs to this java. 给定的数据包括所有CAR_VIN，以避免对此Java进行调出。

Its the xsl logic and code specifically relating to the merging that I'm new to and need some help on. 它的xsl逻辑和代码与我刚接触的合并特别相关，需要一些帮助。

The merge logic is to combine both data sources MANUFACTURERS and child elements. 合并逻辑将数据源MANUFACTURERS和子元素组合在一起。 Where both sources have identical CAR elements whose child elements, CAR_REG_DATE and CAR_MODEL content is the same then only include the data from either Data1.xml or Data2.xml whichever has the highest count of that unique combination. 如果两个源都具有相同的CAR元素，并且其子元素CAR_REG_DATE和CAR_MODEL的内容相同，则仅包含Data1.xml或Data2.xml中的数据，以该唯一组合的最高计数为准。 If a combinaton has the same amount of data in both data sources then use the transformation source xml, in the above case Data1.xml. 如果组合在两个数据源中具有相同数量的数据，则使用转换源xml，在上述情况下为Data1.xml。 The resulting elements need to be ordered by CAR_REG_DATE descending in each individual MANUFATURER element. 生成的元素需要按CAR_REG_DATE在每个MANUFATURER元素中降序排列。 So in the above data example you can see that the necesary output includes all MANUFACTURERS ; 因此，在以上数据示例中，您可以看到必要的输出包括所有MANUFACTURERS； VAUXHALL, FORD, TOYOTA. 沃克斯豪尔，福特，丰田。 In the case of Vauxhall Astra 20060331 the output contains the data from Data2.xml ASTRA 20060331 excluding the same data combination from Data1.xml All other cases of Vauxhall Astra (non 20060331) are included in the ouput from Data1.xml all the CARS in each MANUFACTURER being ordered by CAR_REG_DATE descending Ford Manaufacturer data is included in the output from Data1 ordered CAR_REG_DATE desc. 对于Vauxhall Astra 20060331，输出包含Data2.xml ASTRA 20060331中的数据，但不包括Data1.xml中的相同数据组合。所有其他Vauxhall Astra（非20060331）的情况都包含在Data1.xml的输出中。由CAR_REG_DATE降序排列的Ford Manaufacturer数据降序的每个MANUFACTURER都包含在Data1排序的CAR_REG_DATE desc的输出中。 Toyota Manaufacturer data is included in the output from Data2 ordered CAR_REG_DATE desc. Toyota Manaufacturer数据包含在Data2订购的CAR_REG_DATE desc的输出中。

I initially came up with the idea of merging using the union operator where Data2.xml CAR_REG_DATE and CAR_MODEL content value is not the same as Data1.xml CAR_REG_DATE but this would exclude any data from Data2.xml when there was no matching data CAR_REG_DATE and CAR_MODEL combination in Data1.xml. 我最初想到了使用联合运算符合并的想法，其中Data2.xml CAR_REG_DATE和CAR_MODEL内容值与Data1.xml CAR_REG_DATE不同，但是当没有匹配的数据CAR_REG_DATE和CAR_MODEL时，这将从Data2.xml中排除任何数据Data1.xml中的组合。 Also (when I thought about it) it will allways exclude data from Data2.xsml when the same combination CAR_REG_DATE and CAR_MODEL was in DATA1.xml irrespective of counts in either data source, which is definately not what I want. 同样（当我考虑到这一点），当相同的组合CAR_REG_DATE和CAR_MODEL在DATA1.xml中时，它将始终从Data2.xsml中排除数据，而不管这两个数据源中的计数如何，这绝对不是我想要的。

Result from applying stylesheet.xsl 应用stylesheet.xsl的结果

<?xml version="1.0" encoding="UTF-8"?>

12345678901234567 1.9 ASTRA 20060331 A HH54 RRY RED 12345678901234567 1.9 ASTRA 20040331 A HH54 RRY RED 12345678901234567 2.5 CALIBRA 20030331 A HH54 RRY BLUE 12345678901234567 2.5 CMAX 20050331 A HH54 RRY RED 12345678901234567 1.9 ASTRA 20060331 A HH54 RRY红色12345678901234567 1.9 ASTRA 20040331 A HH54 RRY红色12345678901234567 2.5 CALIBRA 20030331 A HH54 RRY蓝色12345678901234567 2.5 CMAX 20050331 A HH54 RRY红色

hen I came up with the idea of merging both the source document and external document together into a local variable and passing this merged MANUFACTURER into a template and looping through every CAR element. 后来我想到了将源文档和外部文档都合并到局部变量中，然后将合并的MANUFACTURER传递到模板中并遍历每个CAR元素的想法。 I can differentiate between Data1.xml and Data2.xml CAR elements by the content of CAR_VIN starting with XXX.So I thought I would loop through every merged CAR element and select counts for source document and external document and include external or exclude source based on the result. 我可以通过以XXX开头的CAR_VIN的内容来区分Data1.xml和Data2.xml CAR元素。所以我想我将遍历每个合并的CAR元素，并选择源文档和外部文档的计数，并基于以下内容包含外部或排除源结果。

Is this possible and how would I go about doing this or is there a correct way of doing this keeping in mind I am a complete newbie to xslt processing ? 这可能吗，我将如何去做？还是要牢记正确的方法，以确保我是xslt处理的新手？

Any help with this problem would be really appreciated. 对此问题的任何帮助将不胜感激。

Hi thanks for the response 嗨，谢谢你的回复

I've edited the data set to avoid rsi. 我已编辑数据集以避免rsi。

In a nutshell I need to implement the following logic - 简而言之，我需要实现以下逻辑-

Whichever source Data1.xml or Data2.xml has the greater number of unique combination of CAR_REG_DATE and CAR_MODEL (within CAR) include that sources data in the output - exclude the other sources data with the same combination. 不论源Data1.xml或Data2.xml的CAR_REG_DATE和CAR_MODEL唯一组合的数量较多（在CAR内），输出中都包含源数据-排除具有相同组合的其他源数据。

All CAR_REG_DATE - CAR_MODEL unique combinations need to be included from both sources. 这两个来源都必须包含所有CAR_REG_DATE-CAR_MODEL唯一组合。 Ordered CAR_REG_DATE descending in each MANUFACTURER, once merged 一旦合并，在每个MANUFACTURER中降序的CAR_REG_DATE

So taking the Vauxhall MANUFACTURER 因此，选择沃克斯豪尔制造商

unique combination of Astra- 20060331 - Data1.xml has 1 and Data2.xml has 2. Astra- 20060331的唯一组合-Data1.xml具有1和Data2.xml具有2。

I need to output the Astras 20060331 from Data2.xml set for this combination and disregard Data1.xml Astras 20060331 1 occurence as shown in the requiredoutput.xml above 我需要从为此组合设置的Data2.xml中输出Astras 20060331，而忽略Data1.xml Astras 20060331 1的出现，如上面的requiredoutput.xml所示

Dimi I do appreciate your comment . 迪米我非常感谢您的评论。 I think this is my problem; 我认为这是我的问题； I'm trying to look at the problem and break it down into smaller pieces but am failing here. 我试图查看问题并将其分解为较小的部分，但在这里失败了。 I'm still in shock from discovering that the xsl:variable is immutable. 发现xsl：variable是不可变的，我仍然感到震惊。 (or so it seems). （或者看起来）。

Answer 1

This stylesheet: 此样式表：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:key name="kCarByMan-Mod-Date"
             match="CAR"
             use="concat(../@name,'+',CAR_MODEL,'+',CAR_REG_DATE)"/>
    <xsl:variable name="vSource2" select="document('Data2.xml')"/>
    <xsl:template match="node()|@*" name="identity">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="node()|@*" mode="copy">
        <xsl:call-template name="identity"/>
    </xsl:template>
    <xsl:template match="DEALERSHIP">
        <xsl:copy>
            <xsl:apply-templates select="node()|@*">
                <xsl:with-param name="pSource2" select="$vSource2"/>
            </xsl:apply-templates>
            <xsl:apply-templates
                 select="$vSource2/*/MANUFACTURER[
                                        not(@name = current()/*/@name)
                                     ]">
                <xsl:with-param name="pSource2" select="/"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="MANUFACTURER">
        <xsl:param name="pSource2"/>
        <xsl:copy>
            <xsl:apply-templates select="node()|@*">
                <xsl:with-param name="pSource2" select="$pSource2"/>
            </xsl:apply-templates>
            <xsl:apply-templates
                 select="$pSource2/*/MANUFACTURER[
                                        @name = current()/@name
                                     ]/node()">
                <xsl:with-param name="pSource2" select="/"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="CAR"/>
    <xsl:template
         match="CAR[count(.|key('kCarByMan-Mod-Date',
                                concat(../@name,'+',CAR_MODEL,'+',CAR_REG_DATE)
                            )[1]
                    ) = 1]">
        <xsl:param name="pSource2"/>
        <xsl:variable
             name="vKey"
             select="concat(../@name,'+',CAR_MODEL,'+',CAR_REG_DATE)"/>
        <xsl:variable name="vGroup" select="key('kCarByMan-Mod-Date',$vKey)"/>
        <xsl:for-each select="$pSource2">
            <xsl:variable name="vGroup2"
                          select="key('kCarByMan-Mod-Date',$vKey)"/>
            <xsl:apply-templates
                 select="$vGroup[not(count($vGroup2) > count($vGroup))]"
                 mode="copy"/>
        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

Output: 输出：

<DEALERSHIP reg_number="01234567">
    <MANUFACTURER name="VAUXHALL">
        <CAR>
            <CAR_VIN>12345678901234567</CAR_VIN>
            <CAR_ENG>1.9</CAR_ENG>
            <CAR_MODEL>ASTRA</CAR_MODEL>
            <CAR_REG_DATE>20040331</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>HH54 RRY</CAR_REG>
            <COLOUR>RED</COLOUR>
        </CAR>
        <CAR>
            <CAR_VIN>12345678901234567</CAR_VIN>
            <CAR_ENG>2.5</CAR_ENG>
            <CAR_MODEL>CALIBRA</CAR_MODEL>
            <CAR_REG_DATE>20030331</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>HH54 RRY</CAR_REG>
            <COLOUR>BLUE</COLOUR>
        </CAR>
        <CAR>
            <CAR_VIN>XXX12345678901234567</CAR_VIN>
            <CAR_ENG>1.9</CAR_ENG>
            <CAR_MODEL>ASTRA</CAR_MODEL>
            <CAR_REG_DATE>20060331</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>SS00 RRY</CAR_REG>
            <COLOUR>BLUE</COLOUR>
        </CAR>
        <CAR>
            <CAR_VIN>XXX12345678901234567</CAR_VIN>
            <CAR_ENG>1.9</CAR_ENG>
            <CAR_MODEL>ASTRA</CAR_MODEL>
            <CAR_REG_DATE>20060331</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>SS00 RRY</CAR_REG>
            <COLOUR>BLUE</COLOUR>
        </CAR>
    </MANUFACTURER>
    <MANUFACTURER name="FORD">
        <CAR>
            <CAR_VIN>12345678901234567</CAR_VIN>
            <CAR_ENG>2.5</CAR_ENG>
            <CAR_MODEL>CMAX</CAR_MODEL>
            <CAR_REG_DATE>20050331</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>HH54 RRY</CAR_REG>
            <COLOUR>RED</COLOUR>
        </CAR>
    </MANUFACTURER>
    <MANUFACTURER name="TOYOTA">
        <CAR>
            <CAR_VIN>XXX12345678901234567</CAR_VIN>
            <CAR_ENG>1.9</CAR_ENG>
            <CAR_MODEL>Corolla</CAR_MODEL>
            <CAR_REG_DATE>20030812</CAR_REG_DATE>
            <TRANSMISSION>A</TRANSMISSION>
            <CAR_REG>SS00 RRY</CAR_REG>
            <COLOUR>RED</COLOUR>
        </CAR>
    </MANUFACTURER>
</DEALERSHIP>

Note : Grouping by manufacturer, model and date. 注意：按制造商，型号和日期分组。 Traversing Data1.xml . 遍历Data1.xml 。 DEALERSHIP rule (match node from Data1.xml only): copy itself, apply templates to child with Data2.xml as second source, apply templates to manufacturers from Data2.xml not present in Data1.xml . DEALERSHIP规则（从匹配节点Data1.xml唯一的）：自我复制，具有应用模板儿童Data2.xml作为第二个来源，从应用模板厂家Data2.xml不存在Data1.xml 。 MANUFACTURER rule (match nodes from both Data1.xml and Data2.xml ): copy itself, apply templates to children with pSource2 param as second source, apply templates to CAR belonging to the same manufacturer in second source (this would be empty for manufacturers from Data2.xml not present in Data1.xml ). MANUFACTURER规则（匹配来自Data1.xml和Data2.xml节点）：复制自身，将模板应用到具有pSource2参数作为第二个源的子级，将模板应用到第二个源中属于同一制造商的CAR （对于来自Data2.xml不存在Data1.xml ）。 Empty CAR default rule. 空CAR默认规则。 "First in a kind" CAR rule: copy current group if there are no more items in the same group from second source (This means that for equal number, both gets copied. Clarify behaviour if this is not desired. ) “第一种” CAR规则：如果第二个来源的同一组中没有更多项目，则复制当前组（这意味着对于相同数量的项目，两个都将被复制。 如果不需要，请澄清行为。 ）

完成xslt新手。如何在xslt 1.0版中合并这2个xml源。应用分组和排序？

问题描述

1 个解决方案

解决方案1
0

完成xslt新手。 如何在xslt 1.0版中合并这2个xml源。 应用分组和排序？

问题描述

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完成xslt新手。如何在xslt 1.0版中合并这2个xml源。应用分组和排序？

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