[英]PHP timestamp comparison
$today = mktime(0,0,0,2, 9, 2011);
$today >= $r['arrival_date'] // false
9 >= date('j', $r['arrival_date']) // true
$r['arival_date'] is 1297227600 [Feb 9, 2011 07:00]
Simple: 简单:
$today = mktime(0,0,0,2, 9, 2011); // = 1297209600
and 和
$r['arival_date'] = 1297227600;
so 所以
1297227600 > 1297209600
because 因为
date('H',$r['arrival_date']); // 7
date('H',$today); // 0
To expand and explain upon Andre Matos' answer, mktime(0,0,0,2,9,2011);
扩展并解释Andre Matos的答案,
mktime(0,0,0,2,9,2011);
is 00:00:00 Feb 9 2011
, basically the first instant of Feb 9, and the Arrival Date is 07:00:00 Feb 9 2011
, 7 hours later, so it's timestamp is greater than the one created by mktime. 是
00:00:00 Feb 9 2011
,基本上是00:00:00 Feb 9 2011
的第一时刻,到达日期是07:00:00 Feb 9 2011
,即7小时后,因此它的时间戳大于mktime创建的时间戳。
To check whether or not a timestamp falls within a specific day, you can check in a few different ways: 要检查时间戳记是否在特定的一天之内,您可以通过几种不同的方式进行检查:
//You can check by adding a day onto the timestamp for today, 24*60*60 is one days worth of seconds (86400 seconds)
if($r['arrival_date'] >= $today && $r['arrival_date'] <= $today + (24*60*60))
//Or you can mktime for tomorrow too.
$tomorrow = mktime(0,0,0,2,10,2011);
if($r['arrival_date'] >= $today && $r['arrival_date'] <= $tomorrow)
//Or you could check the way you have up there, by running it through date and checking if one is equivalent to another
//Or you could do strtotime in there somewhere, or whatever
That's just a couple of the easiest. 这只是最简单的几个。 Basically since timestamps are down to the second (specifically seconds since
00:00:00 Jan 1 1970 UTC
), you're gonna have to check them by range. 基本上,因为时间戳减少到了第二个(特别是自
00:00:00 Jan 1 1970 UTC
以来的秒),所以您必须按范围检查它们。
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