每月和每周的MySql时间戳查询和比较

Question

i have a table where i enter entries for applicants. it has a column date_added where the type is timestamp and the default is current_timestamp. i want to make a weekly and monthly report but i can't decide what would be the best thing to do. i need an sql statement that return the number of entry like this..

switch($searchby){
case "monthly": $qry = "select * from tblapplicant where date_added > $month"; break;
case "weekly": $qry = "select * from tblapplicant where date_added > $week"; break;
}

$res = mysql_query($select);
$rec_count = mysql_num_rows($res);

echo "There are <font color='red' size='3'>".$rec_count."</font> matching records found.";

i know this is incorrect but this is all i can think at the moment.

another thing i want is, i want it to be the exact year and month report..

edit: output should be: There are 13 applicants for the whole month of June 2013. - or if weekly - There are 3 applicants for the third quarter of July 2013.

Answer 1

I suggest the following approach. First, use your php code to determine the day that your search period begins, and the day after it ends. For example, if it's a monthtly report for September 2013, your start date would be 2013-09-01, and the end date would be 2013-10-01. Then you simply have one query.

 where date_added >= $startdate
 and date_added < $enddate

The major benefits of this approach are:

1. The time component of your timestamp field gets handled.
2. Your query will run reasonably quickly, especially if date_added is indexed.
3. It's easier to sort out programmnig logic with application code than with sql
4. You can write your query as a stored procedure to make it even faster.

Answer 2

This can be your sql statement

select * from tblapplicant where month(date_added) > $month
select * from tblapplicant where DAYOFWEEK(date_added) = X

You should replace X whith your weeek day 1 = Sunday, 2 = Monday, …, 7 = Saturday