Java：定界符和正则表达式

Question

I'm using the scanner method to do work on a string and need to filter out junk

here's the sample string

5/31/1948@14:57

I need to strip out the / @ :

Theres this doc: http://download.oracle.com/javase/1.5.0/docs/api/java/util/regex/Pattern.html

But it's really confusing.

Answer 1

You can use the replaceAll method as:

String filetredStr = inputStr.replaceAll("[@/:]","");

And if you want to delete any non-digit you can do:

String filetredStr = inputStr.replaceAll("[^0-9]","");

Answer 2

如果您想将其拆分，请使用String#split()

String[] parts = "5/31/1948@14:57".split("[/@:]");

Answer 3

做这样的事情：

s.replaceAll("[\\/@:]", "");

Answer 4

An alternative to replaceAll(a,b) is as follows:

String str = "5/31/1948@14:57";
String charsToRemove = "/@:";
for (int i = 0; i < charsToRemove.length(); i++) {
    str = str.replace(charsToRemove.charAt(i)+"", "");
}