简体   繁体   English

SQL获取其他值的MAX

[英]Sql get MAX for other value

I would like to figure out how to select a table where the value is the ID of the person with the highest pay. 我想弄清楚如何选择一个表,该表的值是薪水最高的人的ID。

So if I had 所以如果我有

Table=theJobs 表格=工作

JobID  Pay
----------
12345  10  
12346  12  
12347  13

table=thePerson table = thePerson

Person   JobID   
--------------
Person1  1  
Person2  2  
Person3  3

table=hire(FKs) table =雇用(FKs)

JobID  PersonID
----------------
12345  2  
12347  1  
12346  3

I'd like it to show the max payed person so it should show 我希望它显示最高工资的人,所以它应该显示

Person1

I tried to use where for the a Max function but it seems to fail. 我尝试对max函数使用where,但是它似乎失败了。 I'm pretty sucky at these group functions. 这些组函数让我感到很困惑。 I guess I'm more asking how to use a group function as a constraint than anything. 我想我问的更多的是如何使用组函数作为约束。 Since I had a similar issue a bit ago. 因为我之前有类似的问题。

SELECT p.Person
FROM person p JOIN hire h ON p.PersonID = h.PersonID
  JOIN theJobs j ON h.JobID = j.JobID
ORDER BY j.Pay DESC
LIMIT 1;

If you are using a RDBMS that does not support the LIMIT clause, try using the TOP clause instead: 如果使用的是不支持LIMIT子句的RDBMS,请尝试使用TOP子句:

SELECT TOP 1 p.Person
FROM person p JOIN hire h ON p.PersonID = h.PersonID
  JOIN theJobs j ON h.JobID = j.JobID
ORDER BY j.Pay DESC

This solution will work in pretty much any database system: 该解决方案几乎可以在任何数据库系统中工作:

Select ....
From thePerson As P
    Join    (
            Select H1.PersonId, Max( J1.Pay ) As MaxPay
            From hire As H1
                Join theJobs As J1
                    On J1.JobId = H1.JobID
            Group By H1.PersonId
            ) As PayPerPerson
        On PayPerPerson.PersonId = P.Person
Where Exists    (
                Select 1
                From hire As H2
                    Join theJobs As J2
                        On J2.JobId = H2.JobID
                Where H2.PersonId = P.Person
                Having Max( J2.Pay ) = PayPerPerson.MaxPay
                )

If you are using a DBMS that supports ranking functions and common-table expressions such as SQL Server 2005 and later, then the problem is easier. 如果使用支持排名功能和公用表表达式(例如SQL Server 2005和更高版本)的DBMS,则此问题会更容易。 This solution will show only one name and ignore ties: 此解决方案将仅显示一个名称,并忽略联系:

With RankedPay As
    (
    Select  ...
        , Row_Number() Over( Order By J.Pay Desc ) As Rnk
    From thePerson As P
        Join hire As H
            On H.PersonId = P.Person
        Join theJobs As J
            On J.JobId = H.JobId
    )
Select ...
From RankedPay
Where Rnk = 1

This solution will show any that match the top pay and include ties: 此解决方案将显示所有与最高薪资相匹配并包含平局的人:

With RankedPay As
    (
    Select  ...
        , Rank() Over( Order By J.Pay Desc ) As Rnk
    From thePerson As P
        Join hire As H
            On H.PersonId = P.Person
        Join theJobs As J
            On J.JobId = H.JobId
    )
Select ...
From RankedPay
Where Rnk = 1

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM