[英]Sql get MAX for other value
我想弄清楚如何选择一个表,该表的值是薪水最高的人的ID。
所以如果我有
表格=工作
JobID Pay
----------
12345 10
12346 12
12347 13
table = thePerson
Person JobID
--------------
Person1 1
Person2 2
Person3 3
table =雇用(FKs)
JobID PersonID
----------------
12345 2
12347 1
12346 3
我希望它显示最高工资的人,所以它应该显示
Person1
我尝试对max函数使用where,但是它似乎失败了。 这些组函数让我感到很困惑。 我想我问的更多的是如何使用组函数作为约束。 因为我之前有类似的问题。
SELECT p.Person
FROM person p JOIN hire h ON p.PersonID = h.PersonID
JOIN theJobs j ON h.JobID = j.JobID
ORDER BY j.Pay DESC
LIMIT 1;
如果使用的是不支持LIMIT
子句的RDBMS,请尝试使用TOP
子句:
SELECT TOP 1 p.Person
FROM person p JOIN hire h ON p.PersonID = h.PersonID
JOIN theJobs j ON h.JobID = j.JobID
ORDER BY j.Pay DESC
该解决方案几乎可以在任何数据库系统中工作:
Select ....
From thePerson As P
Join (
Select H1.PersonId, Max( J1.Pay ) As MaxPay
From hire As H1
Join theJobs As J1
On J1.JobId = H1.JobID
Group By H1.PersonId
) As PayPerPerson
On PayPerPerson.PersonId = P.Person
Where Exists (
Select 1
From hire As H2
Join theJobs As J2
On J2.JobId = H2.JobID
Where H2.PersonId = P.Person
Having Max( J2.Pay ) = PayPerPerson.MaxPay
)
如果使用支持排名功能和公用表表达式(例如SQL Server 2005和更高版本)的DBMS,则此问题会更容易。 此解决方案将仅显示一个名称,并忽略联系:
With RankedPay As
(
Select ...
, Row_Number() Over( Order By J.Pay Desc ) As Rnk
From thePerson As P
Join hire As H
On H.PersonId = P.Person
Join theJobs As J
On J.JobId = H.JobId
)
Select ...
From RankedPay
Where Rnk = 1
此解决方案将显示所有与最高薪资相匹配并包含平局的人:
With RankedPay As
(
Select ...
, Rank() Over( Order By J.Pay Desc ) As Rnk
From thePerson As P
Join hire As H
On H.PersonId = P.Person
Join theJobs As J
On J.JobId = H.JobId
)
Select ...
From RankedPay
Where Rnk = 1
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