[英]How to get the value of a CSS property using JQuery?
I am trying to set a box A to jump to the same x-position as box B. How do I do this? 我想设置一个方框A跳到与方框B相同的x位置。我该怎么做? I tried the following but it does not work (the second line):
我尝试了以下但它不起作用(第二行):
$("#boxa").animate({
left: $("#boxb").left
}, 1000, function() { });
});
Thanks, 谢谢,
Sam 山姆
either 或
$('#boxB').css('left');
or 要么
$('#boxB').offset().left;
For properties specified in pixels, using: 对于以像素指定的属性,使用:
$('#boxB').css('padding-left');
gives a string like: '22px' 给出一个字符串:'22px'
Maybe it's better to use: 也许最好使用:
parseInt($('#boxB').css('padding-left'), 10);
in such cases, which gives a number like 22 . 在这种情况下,给出一个像22的数字。
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