[英]JAXB not unmarshalling xml any element to JAXBElement
I have a webservice call. 我有一个网络服务电话。 In my response when I try to get the xml
any
element in to a JAXBElement it throws an error. 在我的响应中,当我尝试将xml中的
any
元素放入JAXBElement时,它会抛出错误。
In the schema I have: 在模式中我有:
<xs:complexType name="InputType">
<xs:annotation></xs:annotation>
<xs:sequence>
<xs:element name="Id" type="xs:string" />
<xs:any namespace="##any" processContents="lax" minOccurs="0" />
</xs:sequence>
</xs:complexType>
The code I am using: 我正在使用的代码:
Object obj = inputType.getAny();
Object o = ((JAXBElement)obj).getValue();
This line throws the error: org.apache.xerces.dom.ElementNSImpl incompatible with javax.xml.bind.JAXBElement
error in soap ui. 此行抛出错误:
org.apache.xerces.dom.ElementNSImpl incompatible with javax.xml.bind.JAXBElement
soap ui中的org.apache.xerces.dom.ElementNSImpl incompatible with javax.xml.bind.JAXBElement
错误org.apache.xerces.dom.ElementNSImpl incompatible with javax.xml.bind.JAXBElement
。
Why doesn't it covert to JAXBElement? 为什么它不转换为JAXBElement? How do I make it work?
我如何使其工作?
If the property is annotated with the following the contents will be mapped as DOM nodes: 如果使用以下内容对属性进行批注,则内容将映射为DOM节点:
@XmlAnyElement
If the lax=true flag is set then known elements will be converted to domain objects: 如果设置了lax = true标志,则已知元素将转换为域对象:
@XmlAnyElement(lax=true)
For more information on @XmlAnyElement see: 有关@XmlAnyElement的更多信息,请参阅:
UPDATE #1 更新#1
With lax=true you can get a mix of domain objects and DOM nodes. 使用lax = true,您可以获得域对象和DOM节点的混合。 The following is from the java docs:
以下是来自java文档:
When true
当真的
If true, when an element matches a property marked with XmlAnyElement is known to JAXBContext (for example, there's a class with XmlRootElement that has the same tag name, or there's XmlElementDecl that has the same tag name), the unmarshaller will eagerly unmarshal this element to the JAXB object, instead of unmarshalling it to DOM.
如果为true,当一个元素与标记为XmlAnyElement的属性匹配时,JAXBContext就知道了(例如,有一个具有相同标记名称的XmlRootElement的类,或者具有相同标记名称的XmlElementDecl),unmarshaller将急切地解组此元素到JAXB对象,而不是将其解组为DOM。 Additionally, if the element is unknown but it has a known xsi:type, the unmarshaller eagerly unmarshals the element to a JAXBElement, with the unknown element name and the JAXBElement value is set to an instance of the JAXB mapping of the known xsi:type.
此外,如果元素未知但它具有已知的xsi:类型,则unmarshaller急切地将元素解组为JAXBElement,其中未知元素名称和JAXBElement值设置为已知xsi:类型的JAXB映射的实例。
As a result, after the unmarshalling, the property can become heterogeneous;
结果,在解组后,财产可能变得异质; it can have both DOM nodes and some JAXB objects at the same time.
它可以同时拥有DOM节点和一些JAXB对象。
UPDATE #2 更新#2
To ultimately solve the problem: 最终解决问题:
Check out my blog for an example: 查看我的博客中的示例:
validate your xml against your schema. 根据您的架构验证您的xml。 that should be the first thing to be checked
这应该是第一件要检查的事情
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