什么在python中定义浮点精度？

Question

I learnt of the "exactly equal to" operator in Erlang, which compares not only values , but also data types of numbers, and I was curious about how things work in Python and its lone "equals to" operator. So after making sure that

>>> 1 == 1.0 
True

I wondered about the floating point precision, and got to this

>>> 0.9999999999999999 == 1
False
>>> 0.99999999999999999 == 1
True
>>>

Could someone explain how floating point precision is determined here? It works the same in both 2.7.1 and 3.1.2

Answer 1

Please check with the Python documentation:

http://docs.python.org/tutorial/floatingpoint.html

Answer 2

It's a peril of using floating-point numbers.

If you need precision at this deep a level, use the Decimal type.

More here: http://docs.python.org/library/decimal.html