如何在SQL中选择表的最后一条记录？

Question

This is a sample code to select all records from a table. Can someone show me how to select the last record of that table?

select * from table

When I use: SELECT * FROM TABLE ORDER BY ID DESC LIMIT I get this error: Line 1: Incorrect syntax near 'LIMIT'. This is the code I use:

private void LastRecord()
{
    SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["HELPDESK_OUTLOOKConnectionString3"].ToString());

    conn.Open();
    SqlDataReader myReader = null;
    SqlCommand myCommand = new SqlCommand("SELECT * FROM HD_AANVRAGEN ORDER BY " +
                "aanvraag_id DESC LIMIT 1", conn);
    myReader = myCommand.ExecuteReader();
    while (myReader.Read())
    {
        TextBox1.Text = (myReader["aanvraag_id"].ToString());
        TextBox1.Text += (myReader["wijziging_nummer"].ToString());
        TextBox1.Text += (myReader["melding_id"].ToString());
        TextBox1.Text += (myReader["aanvraag_titel"].ToString());
        TextBox1.Text += (myReader["aanvraag_omschrijving"].ToString());
        TextBox1.Text += (myReader["doorlooptijd_id"].ToString());
        TextBox1.Text += (myReader["rapporteren"].ToString());
        TextBox1.Text += (myReader["werknemer_id"].ToString());
        TextBox1.Text += (myReader["outlook_id"].ToString());
    }
}

Answer 1

Without any further information, which Database etc the best we can do is something like

Sql Server

SELECT TOP 1 * FROM Table ORDER BY ID DESC

MySql

SELECT * FROM Table ORDER BY ID DESC LIMIT 1

Answer 2

to get the last row of a SQL-Database use this sql string:

SELECT * FROM TableName WHERE id=(SELECT max(id) FROM TableName);

Output:

Last Line of your db!

Answer 3

Assuming you have an Id column:

SELECT TOP 1 *
  FROM table
 ORDER
    BY Id DESC;

Also, this will work on SQL Server. I think that MySQL you might need to use:

SELECT *
  FROM table
 ORDER
    BY Id DESC
 LIMIT 1

But, I'm not 100% sure about this.

EDIT

Looking at the other answers, I'm now 100% confident that I'm correct with the MySQL statement :o)

EDIT

Just seen your latest comment. You could do:

SELECT MAX(Id)
  FROM table

This will get you the highest Id number.

Answer 4

SELECT * FROM TABLE ORDER BY ID DESC LIMIT 1

是的，这是 mysql，SQL Server：

SELECT TOP 1 * FROM Table ORDER BY ID DESC

Answer 5

SELECT * FROM TABLE WHERE id = (SELECT MAX(id) FROM TABLE);

SELECT MAX(id)表示获取表中最大的id它返回一个数字，这是现在使用WHERE id = maxId的最大ID你可以获得id最大的行，这意味着你使用的最后一行自动递增。

Answer 6

SELECT * FROM table ORDER BY Id DESC LIMIT 1

Answer 7

It is always a good practice in your table design to have an automatic row identifier, such as

 [RowID] [int] IDENTITY(1,1) NOT FOR REPLICATION NOT NULL

, then you can identify your last row by

 select * from yourTable where rowID =  @@IDENTITY 

Answer 8

MS SQL Server has supported ANSI SQL FETCH FIRST for many years now:

SELECT * FROM TABLE
ORDER BY ID DESC 
OFFSET 0 ROWS FETCH FIRST 1 ROW ONLY

(Works with most modern databases.)

Answer 9

如果您有一个自增字段（比如ID ），那么您可以执行以下操作： SELECT * FROM foo WHERE ID = (SELECT max(ID) FROM foo)

Answer 10

当您颠倒顺序时，最后一个只是第一个。

Answer 11

Almost all answers assume the ID column is ordered (and perhaps auto incremented). There are situations, however, when the ID column is not ordered, hence the ORDER BY statement makes no sense.

The last inserted ID might not always be the highest ID, it is just the last (unique) entry.

One possible solution for such a situation is to create a row id on the fly:

SET @r = 0;
SELECT * FROM (SELECT *, (@r := @r + 1) AS r_id FROM my_table) AS tmp
    ORDER BY r_id DESC LIMIT 1;

Answer 12

In Oracle, you can do:

SELECT *
FROM (SELECT EMP.*,ROWNUM FROM EMP ORDER BY ROWNUM DESC)
WHERE ROWNUM=1;

This is one of the possible ways.

Answer 13

select ADU.itemid, ADU.startdate, internalcostprice 
from ADUITEMINTERNALCOSTPRICE ADU

right join

   (select max(STARTDATE) as Max_date, itemid 
   from ADUITEMINTERNALCOSTPRICE
   group by itemid) as A

on A.ITEMID = ADU.ITEMID
and startdate= Max_date

Answer 14

I think this should do it.

declare @x int;
select @x = max(id) from table_name;
select * from where id = @x;

Answer 15

If your table has no auto incremented value and otherwise has no good element to order on, you can get the arbitrary order of the items in any collection like this

SELECT
    [item]
FROM (
    SELECT
        *
        , ROW_NUMBER() OVER(PARTITION BY 1 ORDER BY GETDATE()) 'RN'
    FROM [TABLE]
) RDR 
WHERE [RN] = (
    SELECT
        MAX([RN])
    FROM (
        SELECT
            *
            , ROW_NUMBER() OVER(PARTITION BY 1 ORDER BY GETDATE()) 'RN'
        FROM [TABLE]
    ) RDR 
)

An important caveat is that the performance for this is going to be abysmal with larger sets of data.

Answer 16

$sql="SELECT tot_visit FROM visitors WHERE date = DATE(NOW()) - 1 into @s                
$conn->query($sql);
$sql = "INSERT INTO visitors (nbvisit_day,date,tot_visit) VALUES (1,CURRENT_DATE,@s+1)";
$conn->query($sql);

Answer 17

你也可以做这样的事情：

SELECT LAST (column_name) AS LAST_CUSTOMER FROM table_name;

Answer 18

I upvoted Ricardo. Actually max is much efficient than sorting . See the differences. its excellent.

I had to get the last row/update record (timeStamp)

`sqlite> select timeStamp from mypadatav2 order by timeStamp desc limit 1;
 2020-03-11 23:55:00
 Run Time: real 1.806 user 1.689242 sys 0.117062`

`sqlite> select max(timeStamp) from mypadatav2;
 2020-03-11 23:55:00
 Run Time: real 0.553 user 0.412618 sys 0.134340`