[英]Java - Change int to ascii
java有没有办法将int转换为ascii符号?
Do you want to convert int
s to char
s?:要将int
转换为char
吗?:
int yourInt = 33;
char ch = (char) yourInt;
System.out.println(yourInt);
System.out.println(ch);
// Output:
// 33
// !
Or do you want to convert int
s to String
s?或者你想将int
s 转换为String
s?
int yourInt = 33;
String str = String.valueOf(yourInt);
Or what is it that you mean?或者你的意思是什么?
If you first convert the int to a char, you will have your ascii code.如果您首先将 int 转换为 char,您将拥有您的 ascii 代码。
For example:例如:
int iAsciiValue = 9; // Currently just the number 9, but we want Tab character
// Put the tab character into a string
String strAsciiTab = Character.toString((char) iAsciiValue);
There are many ways to convert an int to ASCII (depending on your needs) but here is a way to convert each integer byte to an ASCII character:有很多方法可以将 int 转换为 ASCII(取决于您的需要),但这里有一种将每个整数字节转换为 ASCII 字符的方法:
private static String toASCII(int value) {
int length = 4;
StringBuilder builder = new StringBuilder(length);
for (int i = length - 1; i >= 0; i--) {
builder.append((char) ((value >> (8 * i)) & 0xFF));
}
return builder.toString();
}
For example, the ASCII text for "TEST" can be represented as the byte array:例如,“TEST”的 ASCII 文本可以表示为字节数组:
byte[] test = new byte[] { (byte) 0x54, (byte) 0x45, (byte) 0x53, (byte) 0x54 };
Then you could do the following:然后你可以执行以下操作:
int value = ByteBuffer.wrap(test).getInt(); // 1413829460
System.out.println(toASCII(value)); // outputs "TEST"
...so this essentially converts the 4 bytes in a 32-bit integer to 4 separate ASCII characters (one character per byte). ...所以这实际上将 32 位整数中的 4 个字节转换为 4 个单独的 ASCII 字符(每个字节一个字符)。
You can convert a number to ASCII in java.您可以在 Java 中将数字转换为 ASCII。 example converting a number 1 (base is 10) to ASCII.将数字 1(基数为 10)转换为 ASCII 的示例。
char k = Character.forDigit(1, 10);
System.out.println("Character: " + k);
System.out.println("Character: " + ((int) k));
Output:输出:
Character: 1
Character: 49
In fact in the last answer String strAsciiTab = Character.toString((char) iAsciiValue);事实上在最后一个答案 String strAsciiTab = Character.toString((char) iAsciiValue); the essential part is (char)iAsciiValue which is doing the job (Character.toString useless)必不可少的部分是 (char)iAsciiValue 正在完成这项工作(Character.toString 没用)
Meaning the first answer was correct actually char ch = (char) yourInt;这意味着第一个答案实际上是正确的 char ch = (char) yourInt;
if in yourint=49 (or 0x31), ch will be '1'如果在 yourint=49(或 0x31)中,ch 将是 '1'
In Java, you really want to use Integer.toString to convert an integer to its corresponding String value.在 Java 中,您确实希望使用Integer.toString将整数转换为其对应的 String 值。 If you are dealing with just the digits 0-9, then you could use something like this:如果你只处理数字 0-9,那么你可以使用这样的东西:
private static final char[] DIGITS =
{'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
private static char getDigit(int digitValue) {
assertInRange(digitValue, 0, 9);
return DIGITS[digitValue];
}
Or, equivalently:或者,等效地:
private static int ASCII_ZERO = 0x30;
private static char getDigit(int digitValue) {
assertInRange(digitValue, 0, 9);
return ((char) (digitValue + ASCII_ZERO));
}
The most simple way is using type casting:最简单的方法是使用类型转换:
public char toChar(int c) {
return (char)c;
}
Use Character#toString<\/code> , not
char<\/code> .
使用
Character#toString<\/code> ,而不是
char<\/code> 。
String result = Character.toString( yourAsciiNumber ) ;<\/code><\/pre>
Ex:前任:
Character.toString( 97 ) \/\/ LATIN SMALL LETTER A<\/code><\/pre>
a一个
<\/blockquote>Character.toString( 128_567 ) \/\/ FACE WITH MEDICAL MASK<\/code><\/pre>
😷 😷
<\/blockquote>
char<\/code> is legacy
char<\/code>是遗产
<\/h1>
The
char<\/code> type in Java is legacy, and is essentially broken.
Java 中的
char<\/code>类型是遗留的,本质上是被破坏的。
As a 16-bit<\/a> value,
char<\/code> is incapable of representing most characters defined by
Unicode<\/a> .
作为16 位<\/a>值,
char<\/code>无法表示
Unicode<\/a>定义的大多数字符。
System.out.println( Character.toString( 128_567 )); \/\/ Unicode code points handle full-range of Unicode characters.<\/code><\/pre>
😷 😷
<\/blockquote>System.out.println( ( char ) 128_567 ); \/\/ `char` fails with most Unicode characters.<\/code><\/pre>
See code run live at IdeOne.com<\/a> .查看在 IdeOne.com 上实时运行的代码<\/a>。
Code point码点<\/h1>
Use code point<\/a> integer numbers to represent individual letters.使用代码点<\/a>整数来表示单个字母。
US-ASCII<\/a> is a subset of Unicode. US-ASCII<\/a>是 Unicode 的子集。 So, any US-ASCII number (0-127) is also a Unicode code point (0-1,114,111).因此,任何 US-ASCII 数字 (0-127) 也是一个 Unicode 代码点 (0-1,114,111)。
To change a code point number to a
String<\/code> object containing a single character, call
Character#toString<\/code><\/a> .
要将代码点编号更改为包含单个字符的
String<\/code>对象,请调用
Character#toString<\/code><\/a> 。
String x = Character.toString( 97 ) ;<\/code><\/pre>
a一个
<\/blockquote>See this code run live at IdeOne.com<\/a> .请参阅在 IdeOne.com 上实时运行的代码<\/a>。
"
The most simple way is to get integer and just use the casting operator Ex最简单的方法是获取整数并仅使用强制转换运算符 Ex
int num = 33;
System.out.println((char) num); //Outputs 33
//if you want to find the integer value of character instead.
//Just do the reverse
char ch = '%';
System.out.println((int) ch);
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