你如何在JavaScript中实现一个保护条款？

Question

I want to guard my functions against null-ish values and only continue if there is "defined" value.

After looking around the solutions suggested to double equal to undefined: if (something == undefined) . The problem with this solution is that you can declare an undefined variable.

So my current solution is to check for null if(something == null) which implicetly checks for undefined. And if I want to catch addionalty falsy values I check if(something) .

See tests here: http://jsfiddle.net/AV47T/2/

Now am I missing something here?

Matthias

Answer 1

The standard JS guard is:

if (!x) {
    // throw error
}

!x will catch any undefined , null , false , 0 , or empty string.

If you want to check if a value is valid , then you can do this:

if (Boolean(x)) {
    // great success
}

In this piece, the block is executed if x is anything but undefined , null , false , 0 , or empty string.

-tjw

Answer 2

The only safe way that I know of to guard against really undefined variables (meaning having variable name that were never defined anywhere) is check the typeof :

if (typeof _someUndefinedVarName == "undefined") {
   alert("undefined");
   return;
}

Anything else (including if (!_someUndefinedVarName) ) will fail.

Basic example: http://jsfiddle.net/yahavbr/Cg23P/

Remove the first block and you'll get:

_someUndefinedVarName is not defined

Answer 3

Only recently discovered using '&&' as a guard operator in JS. No more If statements!

var data = {
  person: {
    age: 22,
    name: null
  }
};

var name = data.person.name && doSomethingWithName(data.person.name);

Answer 4

Ternary to the rescue !

(i) => 
    i == 0 ? 1 :
    i == 1 ? 2 :
    i == 2 ? 3 :
    null