如何抛出例外陈述？

Question

HI ! I want to throw exception for the line

BarcodeNo=Long.parseLong(jTextField1.getText())

I done this in a way

BarcodeNo=Long.parseLong(jTextField1.getText()) throw new NumberFormatException("Enter Numbers Only ");

But this way compiler throws error stating ";" required

So anyone can tell me how to do this ?

Thanks

Answer 1

That will already thrown an exception if the text isn't in the right format. If you want to change the exception message , you'd have to catch the exception and throw a new one:

try {
  BarcodeNo = Long.parseLong(jTextField1.getText());
} catch (NumberFormatException e) {
  throw new NumberFormatException("Enter Numbers Only");
}

I wouldn't suggest that you try to use exception message as user-visible messages though - they're more reasonable for logging than for showing an end user.

Answer 2

yes you should put

try
{
BarcodeNo=Long.parseLong(jTextField1.getText());
}
catch(Exception e)
{
throw new NumberFormatException("Enter Numbers Only ");

}