[英]Substring in Python, what is wrong here?
I'm trying to simulate a substring in Python but I'm getting an error: 我正在尝试在Python中模拟子字符串,但出现错误:
length_message = len(update)
if length_message > 140:
length_url = len(short['url'])
count_message = 140 - length_url
update = update["msg"][0:count_message] # Substring update variable
print update
return 0
The error is the following: 错误如下:
Traceback (most recent call last):
File "C:\Users\anlopes\workspace\redes_sociais\src\twitterC.py", line 54, in <module>
x.updateTwitterStatus({"url": "http://xxx.com/?cat=49s", "msg": "Searching for some ....... tips?fffffffffffffffffffffffffffffdddddddddddddddddddddddddddddssssssssssssssssssssssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeedddddddddddddddddddddddddddddddddddddddddddddddfffffffffffffffffffffffffffffffffffffffffffff "})
File "C:\Users\anlopes\workspace\redes_sociais\src\twitterC.py", line 35, in updateTwitterStatus
update = update["msg"][0:count_message]
TypeError: string indices must be integers
I can't do this? 我做不到
update = update["msg"][0:count_message]
The variable "count_message" return "120" 变量“ count_message”返回“ 120”
Give me a clue. 给我点暗示。
Best Regards, 最好的祝福,
I make this call, update["msg"] comes from here 我打这个电话,update [“ msg”]来自这里
x = TwitterC()
x.updateTwitterStatus({"url": "http://xxxx.com/?cat=49", "msg": "Searching for some ...... ....?fffffffffffffffffffffffffffffdddddddddddddddddddddddddddddssssssssssssssssssssssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeedddddddddddddddddddddddddddddddddddddddddddddddfffffffffffffffffffffffffffffffffffffffffffffddddddddddddddddd"})
Are you looping through this code more than once? 您是否多次遍历此代码?
If so, perhaps the first time through update
is a dict, and update["msg"]
returns a string. 如果是这样,也许第一次通过update
就是字典,并且update["msg"]
返回一个字符串。 Fine. 精细。
But you set update
equal to the result: 但是您将update
设置为等于结果:
update = update["msg"][0:int(count_message)]
which is (presumably) a string. (大概是)一个字符串。
If you are looping, the next time through the loop you will have an error because now update
is a string, not a dict
(and therefore update["msg"]
no longer makes sense). 如果要循环,则下次执行循环时将出现错误,因为现在update
是字符串而不是dict
(因此, update["msg"]
不再有意义)。
You can debug this by putting in a print statement before the error: 您可以通过在错误之前放入打印语句来调试此错误:
print(type(update))
or, if it is not too large, 或者,如果不是太大,
print(repr(update))
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