Java继承和泛型

Question

I'm trying to extend an abstract class with generics and I'm running into a problem:

abstract public class SomeClassA<S extends Stuff> {
  protected ArrayList<S> array;

  public SomeClassA(S s) {
    // ...
  }

  public void someMethod() {
    // Some method using the ArrayList
  }

  abstract public void anotherMethod() {
    // ... 
  }
}

Now I want to extend this class with another abstract class so I could override "someMethod". I tried:

abstract public class SomeClassB<Z extends Stuff> extends SomeClassA {

  public SomeClassB(Z z) {
    super(z);
  }

  @Override public void someMethod() {
    // Some method using the ArrayList
  }

}

NetBeans doesn't see any problem with the constructor, but I cannot use the ArrayList from SomeClassA within the method someMethod. So I tried:

abstract public class SomeClassB<Z extends Stuff> extends SomeClassA<S extends Stuff> {

  public SomeClassB(Z z) {
    super(z);
  }

  @Override public void someMethod() {
    // Some method using the ArrayList
  }

}

And now it's just very odd. Everything seems to work (and I can now use the arraylist, but NetBeans says there's a "> expected" in the declaration of SomeClassB and it just won't compile. If possible, I would like:

1. To know how to solve this particular problem.

2. To have a good reference to understand generics.

3. To know if it's any easier in C#.

Answer 1

You will need to pass the generic type to the superclass also, like this:

abstract public class SomeClassB<Z extends Stuff> extends SomeClassA<Z>

Your superclass and subclass will then both use the same generic type. Generic Types are not inherited by subclasses or passed down to superclasses.

Answer 2

为了更好地理解泛型，请参阅有效的Java，第二版 。