sleep（）函数（python）

Question

  if data.find('!google') != -1:
     nick = data.split('!')[ 0 ].replace(':','')
     try:
       gs = GoogleSearch(args)
       gs.results_per_page = 1
       results = gs.get_results()
       for res in results:
         sck.send('PRIVMSG ' + chan + " " + res.title.encode("utf8") + '\r\n')
         sck.send('PRIVMSG ' + chan + " " + res.url.encode("utf8") + '\r\n')
         print
     except SearchError, e:
       sck.send('PRIVMSG ' + chan + " " + "Search failed: %s" % e + " " + '\r\n')

Ok I'm trying to make the script wait a few seconds before another user can "!google" to prevent users from flooding the channel or the bot, not sure if I should use the sleep() function because that might stop the whole script, I just want to make it wait a few seconds before anyone can use "!google" again.

Answer 1

There is a sleep function inside the time module .

However, to make your script not block, you can call the time function in the time module and store that. If the current time is less than that plus, say, five seconds, don't allow them to use it.

For example:

last_google = 0
# somewhere later in the script where last_google is still in scope...
if data.find('!google') != -1:
    if last_google + 5 < time.time():
        # throttled
        return
    last_google = time.time()
    # do something here