grep命令查找文件

Question

I'm looking for a command that use grep to search in /usr/bin for all the files who have 2 links and sort them in ascending.

The second command I'm looking for must use the first one and display just the files that contain the "x"

Thanks you

Answer 1

You can do this direct from grep, eg:

grep -r --include=*.py "HOSTS" .

will search recursively ('-r') under the current directory ('.') in all python files ('*.py') for the string "HOSTS".

Answer 2

This would do

find /usr/bin -links 2 -print0 | xargs -0 ls -adltr

modify the ls to do the sorting you require

find /usr/bin -links 2 -print0 | xargs -0 grep -l "x"

Files containing the "x" :)

---

If you meant: 'contain the x' as 'are executable (x appears in ls -l output), use

find /usr/bin -links 2 -executable -print0 | ls -adltr

To see only dirs:

find /usr/bin -links 2 -type d -executable -print0 | ls -adltr

To see only files:

find /usr/bin -links 2 -type f -executable -print0 | ls -adltr

Note: directories get 2 links by default ( . is a link) so you might want to look for -links 3 with directories