I'm looking for a command that use grep to search in /usr/bin for all the files who have 2 links and sort them in ascending.
The second command I'm looking for must use the first one and display just the files that contain the "x"
Thanks you
You can do this direct from grep, eg:
grep -r --include=*.py "HOSTS" .
will search recursively ('-r') under the current directory ('.') in all python files ('*.py') for the string "HOSTS".
This would do
find /usr/bin -links 2 -print0 | xargs -0 ls -adltr
modify the ls to do the sorting you require
find /usr/bin -links 2 -print0 | xargs -0 grep -l "x"
Files containing the "x" :)
If you meant: 'contain the x' as 'are executable (x appears in ls -l output), use
find /usr/bin -links 2 -executable -print0 | ls -adltr
To see only dirs:
find /usr/bin -links 2 -type d -executable -print0 | ls -adltr
To see only files:
find /usr/bin -links 2 -type f -executable -print0 | ls -adltr
Note: directories get 2 links by default ( .
is a link) so you might want to look for -links 3
with directories
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