多选择器jquery

Question

i've got this ugly jquery selectors..

$('div img').eq(3).css('padding-right', '0'); //multiple of 4...
$('div img').eq(7).css('padding-right', '0');
$('div img').eq(11).css('padding-right', '0');
$('div img').eq(15).css('padding-right', '0');

i have to get all imgages in positioned in 4^ and multiple-of-4 positions...

is there a better code than mine? :-)

Answer 1

是：

$('div img:nth-child(4n+3)').css('padding-right', '0');

Answer 2

You can use nth-child as illustrated here:

http://jsfiddle.net/YdsjY/