使用python接口快速处理opencv图像像素

Question

Using python-interface for OpenCV, one can easily access the pixel of image using [] operator,like this:

img = cv.LoadImage('test.jpg')
pixel = img[10,10]

variable pixel here is a python tuple object like (10,20,30) (3 channels for example), it's not very convenient to process computation since tuple type does not support operator '-' or '+' . If I hope to do a substruction on a pixel like 255 - (10,20,30) , I must code like this:

import numpy as np
pixel = tuple( np.array([255,255,255]) - np.array(pixel) )

is there a faster and easier solution?
Another qustion : is there a way to make a substraction on all pixels, like using a matrix substraction in Matlab: 255 - img (don't use OpenCV build-in function).

Answer 1

You could use cv2array()/array2cv() functions from adaptors.py in the opencv source distribution and perform all your computation using numpy arrays. 255 - imgarr works in this case. Example (stripped-down version of cv2array() for read-only arrays):

assert isinstance(img, cv.iplimage) and img.depth == cv.IPL_DEPTH_8U
a = np.frombuffer(img.tostring(), dtype=np.uint8)
a.shape = img.height, img.width, img.nChannels
print 255 - a