C ++类成员指向全局函数的指针

Question

I want to have a class which has as a member a pointer to a function

here is the function pointer:

typedef double (*Function)(double);

here is a function that fits the function pointer definition:

double f1(double x)
{
    return 0;
}

here is the class definion:

class IntegrFunction
{
public:
    Function* function;
};

and somewhere in the main function i want to do something like this:

IntegrFunction func1;
func1.function = f1;

But, this code does not work.

Is it possible to assign to a class member a function pointer to a global function, declared as above? Or do I have to change something in the function pointer definition?

Thanks,

Answer 1

Replace this:

class IntegrFunction
{
public:
    Function* function;
};

with this:

class IntegrFunction
{
public:
    Function function;
};

Your typedef already creates a pointer-to-function. Declaring Function* function creates a pointer-to-pointer-to-function.

Answer 2

Just replace

Function* function;

to

Function function;

Answer 3

You declare the variable as Function* function , but the Function typedef is already a typedef for a pointer. So the type of the function pointer is just Function (without the *).

Answer 4

Replace

typedef double (*Function)(double);

by

typedef double Function(double);

to typedef the function-type. You can then write the * when using it.

Answer 5

您需要使用address-of运算符来获取标准C ++ 03中的函数指针。

func1.function = &f1;