微软 Excel 2003 | IF 语句

Question

Firstly I'd like to say my knowledge on Excel is fairly limited, and I'm learning as I go, so feel free to input/correct on anything.

I have a set of information formated as follows:

0.7 9.0 598287      
0.7 10.0 598288     
0.9 36.0 9186264        
4.5 298.0 4071637       
4.3 287.0 13896286      
0.9 18.0 4011248    

I need a to create a formula, that takes each peice of data, the first decimal number, the second, and the final string of numbers. I've created a very long - and seemingly good statement, but it doesn't do exactly as I need. My Formula, and the outputs are as follows

=IF(LEN(J194)=14,RIGHT(J194,6),IF(LEN(J194)=15,RIGHT(J194,6),IF(LEN(J194)=16,RIGHT(J194,6),IF(LEN(J194)=17,RIGHT(J194,7),IF(LEN(J194)=18,RIGHT(J194,8),RIGHT(J194,8))))))

   **DATA**             **OUTPUT**       **LENGTH**

0.7 9.0 598287          598287               14
0.7 10.0 598288         598288               15
0.9 36.0 9186264        186264               16
4.5 298.0 4071637       4071637              17
4.3 287.0 13896286      13896286             18
0.9 18.0 4011248        011248               16

The last column is the string length, as you can see - although the lengths of the strings are the same, I get a different output because the characters preceeding are shorter (1 digit,2 digit and 3 digit numbers)

What I need the formula to do, because my strings range from 14-18 characters in length, is to take the last digits no matter the overall cell length. I am also adding an E to the front of each of these numbers via =CONCATENATE - so I cannot overcount.

I'll gladly awnser any questions regarding my problem if clarifaction is needed.

Thanks for taking the time to read over my post!

Answer 1

=RIGHT(J194,LEN(J194)-FIND(" ",J194,FIND(" ",J194)+1))