python 检查模块-python 的问题

Question

how to write a program to "identify the line number of the function call?"

python inspect module provides options to locate the line number but,

def di():
  return inspect.currentframe().f_back.f_lineno 

this python code prints the current line number.

Answer 1

Why not use inspect.stack() ?

def get_caller_lineno():
    frame, _, lineno, _, _, _ = inspect.stack()[1]
    return lineno

Answer 2

I published a wrapper for inspect with simple stackframe addressing covering the stack frame by a single parameter spos :

• https://pypi.python.org/pypi/pysourceinfo/
• https://pythonhosted.org/pysourceinfo/

Eg pysourceinfo.PySourceInfo.getCallerLinenumber(spos=1)

where spos=0 is the lib-function, spos=1 is the caller, spos=2 the caller-of-the-caller, etc.