为什么 ToMatlab[] 在 Matlab 中随机产生无效矩阵（vertcat 错误）？ （包括错误修正）

Question

I've been using ToMatlab[], available at http://library.wolfram.com/infocenter/MathSource/577/ , to convert Mathematica expressions to Matlab in order to numerically simulate a model.

I recently ran into a bug: I try to have Matlab evaluate a function produced by ToMatlab[], but it gives me the following error:

??? Error using ==> vertcat
CAT arguments dimensions are not consistent.

which means I have a non-square matrix (ie, not a matrix). Searched around and found (one) mention of the bug, but no solution is mentioned: http://groups.google.com/forum/#.searchin/comp.soft-sys.math.mathematica/tomatlab/comp.soft-sys.math.mathematica/cxNZC9IYgfQ/2Q6jP4U4hzkJ

Answer 1

Dug into it a little more, and discovered what the problem was: Converting a symbolic matrix using the original ToMatlab[] routine can introduce an error if the foldlines[] routine folds a line with the "..." literal right before an operator that is both binary and unary (such as + and -) and is not separated from its right operand by whitespace (eg, "+5" instead of "+ 5").

Reason being is that the Dot-Dot-Dot symbol "..." are interpreted as spaces in matrices, according to the Matlab documentation. This causes the extra element to be introduced. See the appended examples for an illustration.

I was able to fix this bug by padding the "+" operator by replacing "+" with " + " in the Plus conversion pattern "ToMatlabaux[e_ /; Head[e] === Plus]". I made this and similar (but otherwise insignificant) style modifications to the original ToMatlab[] routine and uploaded it to pastebin here:

http://pastebin.com/TcjErHVT - ToMatlab Bugfix

I attempted to contact Dr. Ojanen about this, but I received an error from his old mail server saying that his username no longer existed there.

I informed Wolfram about this too, but they said that it is up to the contributor to update their code in the Library Archive.

[Appended examples]

EDU>> [3 + 5]
ans =
     8

EDU>> [3 + ...
5]
ans =
     8

EDU>> [3 +...
5]
ans =
     3     5

EDU>> [3 (+ 5)]
ans =
     3     5

EDU>> [3 ...
+5]
ans =
     3     5