[英]Django template question: how to output just the text if the variable has html in it?
I have a lot of variables that has html in them. 我有很多变量,其中包含html。 For example the value of a variable called {{object.name}} is the following: 例如,名为{{object.name}}的变量的值如下:
Play this <a href="#">hot</a> game and see how <b>fun</b> it is!
Is there a filter that can be applied on the variable that will give me just the text: 是否有一个可以应用于变量的过滤器,它只给出了文本:
Play this hot game and see how fun it is!
Without the text being linked or the html being replaced by htmlentities. 没有文本链接或html被htmlentities取代。 Just the text? 只是文字?
You have 3 options to strip the html code: 您有3个选项来删除HTML代码:
Using " safe " filter in your template: 在模板中使用“ 安全 ”过滤器:
{{ object.name|safe }}
Using " autoescape " tag in your template: 在模板中使用“ autoescape ”标记:
{% autoescape off %}
{{ object.name }}
{% endautoescape %}
or declaring it as " safe " in your python code: 或者在python代码中将其声明为“ 安全 ”:
from django.utils.safestring import mark_safe
name = mark_safe(name)
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