为什么double.Parse忽略零的符号？

Question

For example, in:

bool eq = (1 / double.Parse("-0.0")) == (1 / -0.0);

eq will be false .

double.Parse would have to go through some trouble to explicitly ignore the sign for zero, even though not doing that almost never results in a problem. Since I need the raw representation, I had to write my own parsing function which special-cases negative zero and uses double.Parse for everything else.

That's not a big problem, but I'm really wondering why they made the decision to ignore the sign of zero, because it seems to me that not doing so wouldn't be a bad thing.

Answer 1

我不知道该干嘛本身，而是一个潜在的解决方案：如果你看到一个-开头的性格，解析字符串的其余部分，然后否定它。

Answer 2

There is the difference:

1. double.Parse("-0.0") = 0, 1/0 -> INF

2. 1/-0.0 -> -INF

But the minus operator in statement 2 doesn't mean "-0.0".