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如何检查两个字符串是否包含相同的字母?

[英]How to check if two strings contain the same letters?

$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";

if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}

What if statement am I looking for? if我要找的话怎么办?

I suppose a solution could be to, considering the two following variables : 考虑到以下两个变量,我想一个解决方案可能是:

$textone = "pate";
$texttwo = "tape";


1. First, split the strings, to get two arrays of letters : 1.首先,拆分字符串,得到两个字母数组:

$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);

Note that, as pointed out by @Mike in his comment, instead of using preg_split() like I first did, for such a situation, one would be better off using str_split() : 请注意,正如@Mike在他的评论中所指出的,不是像我第一次那样使用preg_split() ,对于这种情况,最好使用str_split()

$arr1 = str_split($textone);
$arr2 = str_split($texttwo);


2. Then, sort those array, so the letters are in alphabetical order : 2.然后,对这些数组进行排序,因此字母按字母顺序排列:

sort($arr1);
sort($arr2);


3. After that, implode the arrays, to create words where all letters are in alphabetical order : 3.在此之后,破灭的阵列,要创造一个所有的字母按字母顺序排列的话

$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);


4. And, finally, compare those two words : 4.最后,比较这两个

if ($text1Sorted == $text2Sorted) {
    echo "$text1Sorted == $text2Sorted";
}
else {
    echo "$text1Sorted != $text2Sorted";
}



Turning this idea into a comparison function would give you the following portion of code : 将这个想法变成比较函数会给你以下代码部分:

function compare($textone, $texttwo) {
    $arr1 = str_split($textone);
    $arr2 = str_split($texttwo);

    sort($arr1);
    sort($arr2);

    $text1Sorted = implode('', $arr1);
    $text2Sorted = implode('', $arr2);

    if ($text1Sorted == $text2Sorted) {
        echo "$text1Sorted == $text2Sorted<br />";
    }
    else {
        echo "$text1Sorted != $text2Sorted<br />";
    }
}


And calling that function on your two words : 并在你的两个单词上调用该函数:

compare("pate", "tape");
compare("pate", "tapp");

Would get you the following result : 会得到以下结果:

aept == aept
aept != appt

use === and !== 使用===!==

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}else{
    echo "The two strings NOT contain the same letters";
}

or 要么

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}

if ($textone !== $texttwo) {
    echo "The two strings NOT contain the same letters";
}

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