如何檢查兩個字符串是否包含相同的字母？

Question

$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";

if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}

if我要找的話怎么辦？

Answer 1

考慮到以下兩個變量，我想一個解決方案可能是：

$textone = "pate";
$texttwo = "tape";

1.首先，拆分字符串，得到兩個字母數組：

$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);

請注意，正如@Mike在他的評論中所指出的，不是像我第一次那樣使用preg_split() ，對於這種情況，最好使用str_split() ：

$arr1 = str_split($textone);
$arr2 = str_split($texttwo);

2.然后，對這些數組進行排序，因此字母按字母順序排列：

sort($arr1);
sort($arr2);

3.在此之后，破滅的陣列，要創造一個所有的字母按字母順序排列的話 ：

$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);

4.最后，比較這兩個詞 ：

if ($text1Sorted == $text2Sorted) {
    echo "$text1Sorted == $text2Sorted";
}
else {
    echo "$text1Sorted != $text2Sorted";
}

---

將這個想法變成比較函數會給你以下代碼部分：

function compare($textone, $texttwo) {
    $arr1 = str_split($textone);
    $arr2 = str_split($texttwo);

    sort($arr1);
    sort($arr2);

    $text1Sorted = implode('', $arr1);
    $text2Sorted = implode('', $arr2);

    if ($text1Sorted == $text2Sorted) {
        echo "$text1Sorted == $text2Sorted<br />";
    }
    else {
        echo "$text1Sorted != $text2Sorted<br />";
    }
}

並在你的兩個單詞上調用該函數：

compare("pate", "tape");
compare("pate", "tapp");

會得到以下結果：

aept == aept
aept != appt

Answer 2

使用===和!==

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}else{
    echo "The two strings NOT contain the same letters";
}

要么

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}

if ($textone !== $texttwo) {
    echo "The two strings NOT contain the same letters";
}