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如何模拟不存在的find_first_not_of函数?

[英]How to simulate the nonexistent find_first_not_of function?

The std::basic_string class template has member functions find_first_of and find_first_not_of . std::basic_string类模板具有成员函数find_first_offind_first_not_of

The <algorithm> header, however, contains only a generic find_first_of . 但是, <algorithm>标头只包含一个通用的find_first_of

Question1: Is the absence of 问题1:是否缺席

std::find_first_not_of(Iter1 first1, Iter1 last1, Iter2 first2, Iter2 last2)

just an oversight (as for example copy_if ) or is it intentionally omitted because the behavior can be achieved with another standard function? 只是疏忽(例如copy_if )或是故意省略,因为行为可以用另一个标准函数实现?

Of course I could write my own find_first_not_of , but 当然我可以写自己的find_first_not_of ,但是

Question2: Is there a ready workaround somewhere in <algorithm> ? 问题2: <algorithm>某处是否有现成的解决方法? For example, the absence of copy_if is compensated by the presence of remove_copy_if 例如,缺少copy_if可以通过remove_copy_if的存在来补偿

Thanks in advance 提前致谢

I had this same problem, the short answer to your question: it's not possible with the standard stl libraries (although it is possible with boost::phoenix). 我有同样的问题,对你的问题的简短回答:使用标准的stl库是不可能的(虽然有可能使用boost :: phoenix)。

However, you can write your own closure surrounding the sequence iterators that accepts a parameterized 'Value' variable and returns a bool result. 但是,您可以编写自己的闭包,围绕接受参数化“Value”变量并返回bool结果的序列迭代器。

 template<class Iterator> struct is_not_in_range
{
    Iterator const begin;
    Iterator const end;
is_not_in_range(Iterator const& b, Iterator const& e)
    :   begin(b)
    ,   end(e) {}
    template<class Value> bool operator()(Value & v)
    {
          return std::find(begin,end,v) == end;
    }
};

Then you can do this 然后你就可以做到这一点

std::find_if(begin1, end1,  is_not_in_range<Iterator2>(begin2,end2));

Alternatively, you can write a version that uses less branching, but requires a break->continue (approximated with a goto statement) 或者,您可以编写使用较少分支的版本,但需要break-> continue(使用goto语句近似)

template<class Iterator1, class Iterator2> Iterator1 find_first_not_of
(   Iterator1 const& begin1
,   Iterator1 const& end1
,   Iterator2 const& begin2
,   Iterator2 const& end2 )
{
    for(Iterator1 mid1 = begin1; mid1 != end1; ++mid1)
    {
        for(Iterator2 mid2 = begin2; mid2 != end2; ++mid2)
            if(*mid1 == *mid2)
                goto FOUND;
        return mid1;
FOUND:      ;
    }
    return end1;
};

There are new functions added in latest STL ( Jump to ). 最新的STL( 跳转到 )中添加了新功能。

all_of , any_of , none_of , find_if_not , copy_if etc. all_ofany_ofnone_offind_if_notcopy_if等。

I'm not sure about your first question but I think the best you can do is find_if: 我不确定你的第一个问题,但我认为你能做的最好的是find_if:

template <class Iter>
class Check
{
public:
    Check(Iter first, Iter last) : first_(first), last_(last) { }
    template <class T>
    bool operator()(const T& item) { return std::find(first, last, item) == last; }
private:
    Iter first_;
    Iter last_;
};

find_if(first1, last1, Check<Iter2>(first2, last2));

It's easy to write one: 写一个很容易:

pos = std::find(search_list.begin()...)
if (pos!= npos)
{
   pos = std::find(black_list.begin()...)
   if (pos!= npos)
   {
       continue search
   }
   else
  {
      found !!
  }
}
else
{
   not found
}

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