[英]How can I get the highest value in a column by sorting the date in a CSV file using Python?
How can I get the highest value in a column by sorting the date in a CSV file using Python? 如何通过使用Python对CSV文件中的日期进行排序来获取列中的最大值?
My code: 我的代码:
if sys.argv[1] == "-p":
c = sys.argv[2]
col_name= r"\\DT001\Process(SK)\Virtual"
#d = sys.argv[3]
col_name2 = r"(PDH-CSV 4.0) (GMT Standard Time)(0)"
with open(c, 'rb') as inf:
reader = csv.reader(inf)
col_index = next(reader).index(col_name)
highest = float(max(rec[col_index] for rec in reader))
reader2 = csv.reader2(inf)
col_index2 = next(reader).index(col_name2)
date = '7/19/2011'
#gigabytes = highest / 1073741824
gigabytes = highest /1024/1024/1024
print "Performance Counters Peak:\n", gigabytes, "GB"
I was able to sort the highest value but I am unable to figure out how to get the highest value by sorting the desired date in the CSV file using the Python script. 我能够对最大值进行排序,但无法通过使用Python脚本在CSV文件中对所需日期进行排序来弄清楚如何获得最大值。
use this snippet 使用此片段
from time import strptime
def filterByDate(mydate , start,end):
format = "%m/%d/%Y"
return strptime(start,format) <= strptime(mydate,format) and strptime(mydate,format) <= strptime(end,format)
...
...
highest = float(max(rec[col_index] for rec in reader if filterByDate(rec[date_col_index],startDate,endDate)))
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