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[英]How would I get the value of first or second column in csv file given the value of last column using python
[英]How can I get the highest value in a column by sorting the date in a CSV file using Python?
如何通過使用Python對CSV文件中的日期進行排序來獲取列中的最大值?
我的代碼:
if sys.argv[1] == "-p":
c = sys.argv[2]
col_name= r"\\DT001\Process(SK)\Virtual"
#d = sys.argv[3]
col_name2 = r"(PDH-CSV 4.0) (GMT Standard Time)(0)"
with open(c, 'rb') as inf:
reader = csv.reader(inf)
col_index = next(reader).index(col_name)
highest = float(max(rec[col_index] for rec in reader))
reader2 = csv.reader2(inf)
col_index2 = next(reader).index(col_name2)
date = '7/19/2011'
#gigabytes = highest / 1073741824
gigabytes = highest /1024/1024/1024
print "Performance Counters Peak:\n", gigabytes, "GB"
我能夠對最大值進行排序,但無法通過使用Python腳本在CSV文件中對所需日期進行排序來弄清楚如何獲得最大值。
使用此片段
from time import strptime
def filterByDate(mydate , start,end):
format = "%m/%d/%Y"
return strptime(start,format) <= strptime(mydate,format) and strptime(mydate,format) <= strptime(end,format)
...
...
highest = float(max(rec[col_index] for rec in reader if filterByDate(rec[date_col_index],startDate,endDate)))
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