[英]Specialize function template result
I'm pretty new to template metaprogramming and can't find my thinking error in this approach: 我是模板元编程的新手,在这种方法中找不到我的思维错误:
template <typename T>
typename T::ReturnType Query(const std::string& Str);
template <>
ResultTypeRowCount Query(const std::string& Str) { return this->queryRowCount(Str); }
ResultTypeRowCount implements a public typedef with the name ReturnType ResultTypeRowCount实现名称为ReturnType的公共typedef
Thankyou for reading 谢谢您的阅读
It should be: 它应该是:
template <>
ResultTypeRowCount::ReturnType Query<ResultTypeRowCount>(const std::string& Str) { return this->queryRowCount(Str); }
Specializing your template should follow this pattern: 专门化模板应遵循以下模式:
template<typename T>
void foo() {
}
template<>
void foo<int>() {
}
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