如何解析具有名称属性的xml节点

Question

I have an XML file that looks like:

<sizes>
<size name="original" width="386" height="429">
http://userserve-ak.last.fm/serve/_/62380831/Adele+PNG.png
</size>
<size name="large" width="126" height="140">http://userserve-ak.last.fm/serve/126/62380831.png</size>
<size name="largesquare" width="126" height="126">
http://userserve-ak.last.fm/serve/126s/62380831.png
</size>
<size name="medium" width="64" height="71">http://userserve-ak.last.fm/serve/64/62380831.png</size>
<size name="small" width="34" height="38">http://userserve-ak.last.fm/serve/34/62380831.png</size>
<size name="extralarge" width="252" height="280">http://userserve-ak.last.fm/serve/252/62380831.png</size>
</sizes>

How would I get it to parse only the size node with the name "small" ?

So far I have the code:

echo $xml->images->image->sizes->size;

which works but it takes the first image, and I want to specifically locate the small image.

Answer 1

Will the small image always be the fifth one? If so, you could use

$xml->images->image->sizes->size[4];

Answer 2

$xml->images->image->sizes->size['name'] ...should work good for getting any of them. No matter how you do it, you'll want to watch out for the fact that the attribute is an object and in your situation you probably want it to be a string. Which means you'll need to convert it to a string from an object, and you can do that with the (string) , like this:

foreach ($xml->size as $size) {
    $the_size = (string) size['name'];
    print $the_size . "<br>";
}

That gets all of them & turns them into strings, so you can use string functions like strstr() or strcmp() .