用PHP preg_replace

Question

I would like to replace ":" with "\\xEF\\xBC\\x9A" however, I do not want to do this for : that follows "http", "https", and string with the format of @[{numbers}:{numbers}:{some text}]. What I have doesn't really work as (?<!@\\[\\d) does not check what's after it. My current implementation only work for something like @[1:2:text] . Thanks!

$string=preg_replace('#(?<!https)(?<!http)(?<!@\[\d)(?<!@\[\d:\d):#', "\xEF\xBC\x9A", $string);

Answer 1

尝试这个：

preg_replace('/(@\[\d+:\d+:[^]]*]|https?:)|:/e', '"$1"?"$1":"\xEF\xBC\x9A"', $string);

Answer 2

Try this regex:

(?<!@\[(?::?[\d]{0,5}){1,2})(?<!https?):

It should match the first and second instances of ' : ' here.

: test: http: @[1:2:text]

Usage Sample:

$string = preg_replace('/(?<!@\[(?::?[\d]{0,5}){1,2})(?<!https?):/', '\xEF\xBC\x9A', $string);