[英]How can I convert a datetime object to milliseconds since epoch (unix time) in Python?
I have a Python datetime
object that I want to convert to unix time, or seconds/milliseconds since the 1970 epoch.我有一个 Python datetime
对象,我想将其转换为 unix 时间,或自 1970 纪元以来的秒/毫秒。
How do I do this?我该怎么做呢?
It appears to me that the simplest way to do this is在我看来,最简单的方法是
import datetime
epoch = datetime.datetime.utcfromtimestamp(0)
def unix_time_millis(dt):
return (dt - epoch).total_seconds() * 1000.0
In Python 3.3, added new method timestamp
:在 Python 3.3 中,添加了新方法timestamp
:
import datetime
seconds_since_epoch = datetime.datetime.now().timestamp()
Your question stated that you needed milliseconds, which you can get like this:你的问题说你需要毫秒,你可以这样得到:
milliseconds_since_epoch = datetime.datetime.now().timestamp() * 1000
If you use timestamp
on a naive datetime object, then it assumed that it is in the local timezone.如果您在原始日期时间对象上使用timestamp
,则它假定它位于本地时区。 Use timezone-aware datetime objects if this is not what you intend to happen.如果这不是您打算发生的,请使用时区感知日期时间对象。
>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000
1312908481000
Or the help of the time module (and without date formatting):或者时间模块的帮助(没有日期格式):
>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0
Answered with help from: http://pleac.sourceforge.net/pleac_python/datesandtimes.html在以下帮助下回答: http : //pleac.sourceforge.net/pleac_python/datesandtimes.html
Documentation:文档:
You can use Delorean to travel in space and time!您可以使用Delorean 进行时空旅行!
import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch
http://delorean.readthedocs.org/en/latest/quickstart.html http://delorean.readthedocs.org/en/latest/quickstart.html
This is how I do it:这就是我的做法:
from datetime import datetime
from time import mktime
dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0
millis_since_epoch = sec_since_epoch * 1000
Recommendedations from the Python 2.7 docs for the time
module Python 2.7 文档中针对time
模块的建议
from datetime import datetime
from calendar import timegm
# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
if dttm is None:
dttm = datetime.utcnow()
return timegm(dttm.utctimetuple())
print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))
Here's another form of a solution with normalization of your time object:这是另一种形式的时间对象标准化解决方案:
def to_unix_time(timestamp):
epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
delta = my_time - epoch
return delta.total_seconds() * 1000.0
>>> import datetime
>>> import time
>>> import calendar
>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)
>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9, tm_wday=1, tm_yday=78, tm_isdst=-1)
>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009
>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0
[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple [1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple
[2] http://docs.python.org/2/library/time.html [2] http://docs.python.org/2/library/time.html
A bit of pandas code:一些熊猫代码:
import pandas
def to_millis(dt):
return int(pandas.to_datetime(dt).value / 1000000)
import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000
Here is a function I made based on the answer above这是我根据上面的答案制作的功能
def getDateToEpoch(myDateTime):
res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
return res
You can wrap the returned value like this : str(int(res)) To return it without a decimal value to be used as string or just int (without the str)您可以像这样包装返回的值: str(int(res)) 返回它没有十进制值用作字符串或只是 int (没有 str)
A lot of these answers don't work for python 2 or don't preserve the milliseconds from the datetime.许多这些答案不适用于 python 2 或不保留日期时间的毫秒数。 This works for me这对我有用
def datetime_to_ms_epoch(dt):
microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
return int(round(microseconds / float(1000)))
This other solution for covert datetime to unixtimestampmillis.将隐蔽日期时间转换为 unixtimestampmillis 的另一种解决方案。
private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);
public static long GetCurrentUnixTimestampMillis()
{
DateTime localDateTime, univDateTime;
localDateTime = DateTime.Now;
univDateTime = localDateTime.ToUniversalTime();
return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
}
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