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如何在 Python 中將日期時間對象轉換為自紀元(unix 時間)以來的毫秒數?

[英]How can I convert a datetime object to milliseconds since epoch (unix time) in Python?

我有一個 Python datetime對象,我想將其轉換為 unix 時間,或自 1970 紀元以來的秒/毫秒。

我該怎么做呢?

在我看來,最簡單的方法是

import datetime

epoch = datetime.datetime.utcfromtimestamp(0)

def unix_time_millis(dt):
    return (dt - epoch).total_seconds() * 1000.0

在 Python 3.3 中,添加了新方法timestamp

import datetime
seconds_since_epoch = datetime.datetime.now().timestamp()

你的問題說你需要毫秒,你可以這樣得到:

milliseconds_since_epoch = datetime.datetime.now().timestamp() * 1000

如果您在原始日期時間對象上使用timestamp ,則它假定它位於本地時區。 如果這不是您打算發生的,請使用時區感知日期時間對象。

>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000 
1312908481000

或者時間模塊的幫助(沒有日期格式):

>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0

在以下幫助下回答: http : //pleac.sourceforge.net/pleac_python/datesandtimes.html

文檔:

您可以使用Delorean 進行時空旅行!

import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch

http://delorean.readthedocs.org/en/latest/quickstart.html

這就是我的做法:

from datetime import datetime
from time import mktime

dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0

millis_since_epoch = sec_since_epoch * 1000
from datetime import datetime
from calendar import timegm

# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
    if dttm is None:
       dttm = datetime.utcnow()

    return timegm(dttm.utctimetuple())

print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))

這是另一種形式的時間對象標准化解決方案:

def to_unix_time(timestamp):
    epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
    my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
    delta = my_time - epoch
    return delta.total_seconds() * 1000.0
>>> import datetime
>>> import time
>>> import calendar

>>> #your datetime object
>>> now = datetime.datetime.now()
>>> now
datetime.datetime(2013, 3, 19, 13, 0, 9, 351812)

>>> #use datetime module's timetuple method to get a `time.struct_time` object.[1]
>>> tt = datetime.datetime.timetuple(now)
>>> tt
time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9,     tm_wday=1, tm_yday=78, tm_isdst=-1)

>>> #If your datetime object is in utc you do this way. [2](see the first table on docs)
>>> sec_epoch_utc = calendar.timegm(tt) * 1000
>>> sec_epoch_utc
1363698009

>>> #If your datetime object is in local timeformat you do this way
>>> sec_epoch_loc = time.mktime(tt) * 1000
>>> sec_epoch_loc
1363678209.0

[1] http://docs.python.org/2/library/datetime.html#datetime.date.timetuple

[2] http://docs.python.org/2/library/time.html

一些熊貓代碼:

import pandas

def to_millis(dt):
    return int(pandas.to_datetime(dt).value / 1000000)
import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000

這是我根據上面的答案制作的功能

def getDateToEpoch(myDateTime):
    res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
    return res

您可以像這樣包裝返回的值: str(int(res)) 返回它沒有十進制值用作字符串或只是 int (沒有 str)

許多這些答案不適用於 python 2 或不保留日期時間的毫秒數。 這對我有用

def datetime_to_ms_epoch(dt):
    microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
    return int(round(microseconds / float(1000)))

將隱蔽日期時間轉換為 unixtimestampmillis 的另一種解決方案。

private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc);

    public static long GetCurrentUnixTimestampMillis()
    {
        DateTime localDateTime, univDateTime;
        localDateTime = DateTime.Now;          
        univDateTime = localDateTime.ToUniversalTime();
        return (long)(univDateTime - UnixEpoch).TotalMilliseconds;
    } 

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