Javascript正则表达式删除空格

Question

So i'm writing a tiny little plugin for JQuery to remove spaces from a string. see here

(function($) {
    $.stripSpaces = function(str) {
        var reg = new RegExp("[ ]+","g");
        return str.replace(reg,"");
    }
})(jQuery);

my regular expression is currently [ ]+ to collect all spaces. This works.. however It doesn't leave a good taste in my mouth.. I also tried [\\s]+ and [\\W]+ but neither worked..

There has to be a better (more concise) way of searching for only spaces.

Answer 1

I would recommend you use the literal notation, and the \\s character class:

//..
return str.replace(/\s/g, '');
//..

There's a difference between using the character class \\s and just ' ' , this will match a lot more white-space characters, for example '\\t\\r\\n' etc.., looking for ' ' will replace only the ASCII 32 blank space.

The RegExp constructor is useful when you want to build a dynamic pattern, in this case you don't need it.

Moreover, as you said, "[\\s]+" didn't work with the RegExp constructor, that's because you are passing a string, and you should "double escape" the back-slashes, otherwise they will be interpreted as character escapes inside the string (eg: "\\s" === "s" (unknown escape)).

Answer 2

"foo is bar".replace(/ /g, '')

Answer 3

Remove all spaces in string

// Remove only spaces
`
Text with spaces 1 1     1     1 
and some
breaklines

`.replace(/ /g,'');
"
Textwithspaces1111
andsome
breaklines

"

// Remove spaces and breaklines
`
Text with spaces 1 1     1     1
and some
breaklines

`.replace(/\s/g,'');
"Textwithspaces1111andsomebreaklines"

Answer 4

In production and works across line breaks

This is used in several apps to clean user-generated content removing extra spacing/returns etc but retains the meaning of spaces.

text.replace(/[\n\r\s\t]+/g, ' ')

Answer 5

str.replace(/\s/g,'')

Works for me.

jQuery.trim has the following hack for IE, although I'm not sure what versions it affects:

// Check if a string has a non-whitespace character in it
rnotwhite = /\S/

// IE doesn't match non-breaking spaces with \s
if ( rnotwhite.test( "\xA0" ) ) {
    trimLeft = /^[\s\xA0]+/;
    trimRight = /[\s\xA0]+$/;
}

Answer 6

这也适用： http : //jsfiddle.net/maniator/ge59E/3/

var reg = new RegExp(" ","g"); //<< just look for a space.