So i'm writing a tiny little plugin for JQuery to remove spaces from a string. see here
(function($) {
$.stripSpaces = function(str) {
var reg = new RegExp("[ ]+","g");
return str.replace(reg,"");
}
})(jQuery);
my regular expression is currently [ ]+
to collect all spaces. This works.. however It doesn't leave a good taste in my mouth.. I also tried [\\s]+
and [\\W]+
but neither worked..
There has to be a better (more concise) way of searching for only spaces.
I would recommend you use the literal notation, and the \\s
character class:
//..
return str.replace(/\s/g, '');
//..
There's a difference between using the character class \\s
and just ' '
, this will match a lot more white-space characters, for example '\\t\\r\\n'
etc.., looking for ' '
will replace only the ASCII 32 blank space.
The RegExp
constructor is useful when you want to build a dynamic pattern, in this case you don't need it.
Moreover, as you said, "[\\s]+"
didn't work with the RegExp
constructor, that's because you are passing a string, and you should "double escape" the back-slashes, otherwise they will be interpreted as character escapes inside the string (eg: "\\s" === "s"
(unknown escape)).
"foo is bar".replace(/ /g, '')
Remove all spaces in string
// Remove only spaces
`
Text with spaces 1 1 1 1
and some
breaklines
`.replace(/ /g,'');
"
Textwithspaces1111
andsome
breaklines
"
// Remove spaces and breaklines
`
Text with spaces 1 1 1 1
and some
breaklines
`.replace(/\s/g,'');
"Textwithspaces1111andsomebreaklines"
This is used in several apps to clean user-generated content removing extra spacing/returns etc but retains the meaning of spaces.
text.replace(/[\n\r\s\t]+/g, ' ')
str.replace(/\s/g,'')
Works for me.
jQuery.trim
has the following hack for IE, although I'm not sure what versions it affects:
// Check if a string has a non-whitespace character in it
rnotwhite = /\S/
// IE doesn't match non-breaking spaces with \s
if ( rnotwhite.test( "\xA0" ) ) {
trimLeft = /^[\s\xA0]+/;
trimRight = /[\s\xA0]+$/;
}
这也适用: http : //jsfiddle.net/maniator/ge59E/3/
var reg = new RegExp(" ","g"); //<< just look for a space.
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