如何在bash shell脚本中删除文件扩展名？

Question

I have temp.tar.gz in $1
How do I get just 'temp' in another variable ?

I am using bash.
Thanks in advance.

Answer 1

使用bash参数扩展 ：

echo ${1%%.*}

Answer 2

使用bash

echo ${string%%.*}

Answer 3

Using bash and GNU parallel :

$ myFilename=`find . -maxdepth 1 -name *.gz -print0 | parallel -0 echo {.} | parallel -0 echo {.}`
$ echo $myFilename
./temp

Not as clean as the other approaches, for sure, but it will work with filenames with spaces in them.