python将多余的float保存到int转换

Question

x=10.5
    if x==10.5:
        x=int(x)+1
        y= .5

ok i have x=10.5 i want to round up to 11 but say the .5 to use later is there any way to do this when i dont know what x will be all the time?

i have to real place to start or even if its possible i do know how to change it to an int but i want to store what ever it took off and store to y right now id have to write 100 of if statments to figure what do say and that just doent strike me as the best way to do it

Answer 1

One fell swoop:

>>> divmod(10.5,1)
(10.0, 0.5)

The docs for divmod can be found here .

Answer 2

x = 10.5
x,chopped = int(x), x - int(x)

Answer 3

take the number modulus 1

>>> 10.5%1
0.5

Answer 4

This question is rather poorly worded. Is this what you are trying to do?

x = 10.5

y = math.fmod(x, 1.0) # y = 0.5
x = math.ceil(x) # x = 11.0