将struct转换为char

Question

I have a problem where I need to convert a the name of a struct variable into a char . For example:

struct CARINFO a;

When my function takes an argument of CARINFO a , I want to use both a and "a" in the function.

Can anyone help?

Answer 1

You can use a macro to pass both the pointer to your struct and its name to the actual function.

struct bar {
    // blah
};

void actual_foo(struct bar *b, char *bname) {
    // whatever
}

#define foo(bar) actual_foo(&(bar), #bar)

int main() {
    struct bar b;
    foo(b);
}

Answer 2

The best you can do in C is to use a single macro to define both the string and the variable. There's no runtime inspection that would allow you to rediscover the name of a variable.

Answer 3

You could do it by making the function into a macro, and using the # operator (stringification) to get the name of hte argument.

For example:

#define MYFUNC(x) \
do { real_func(x); printf("parameter name: " #x "\n"); } while (0)