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使用xts的%*%的R idiom

[英]R idiom for %*% using xts

I am working with some code that uses the %*% operator to apply vectors of weights to vectors representing time series. 我正在使用一些使用%*%运算符的代码将权重向量应用于表示时间序列的向量。 I would like to use xts for the time series, but the %*% operator is not understanding that it should ignore the xts index values. 我想使用xts作为时间序列,但%*%运算符不理解它应该忽略xts索引值。

I know I can use coredata() to pull out my series values as a vector, operate on the values, and merge them back in, but I was wondering whether there was a good native xts function I should be using. 我知道我可以使用coredata()将我的系列值作为向量拉出,对值进行操作,并将它们合并回来,但我想知道是否有一个好的本机xts函数我应该使用。

EDIT: code sample illustrating the difference I'm seeing in behavior. 编辑:代码示例说明我在行为中看到的差异。

library(xts)
data(sample_matrix)
s<-as.xts(sample_matrix)

o_xts<-s$Open
c_xts<-coredata(s$Open)

len <-length(c_xts)
len2<-len/2
xx<-c_xts[1:len]
outp<-0*0:len2
outp[2] <- xx%*%exp((1:(2*len2))*1.i*pi/len2)
#completes without issue

len <-length(o_xts)
len2<-len/2
yy<-o_xts[1:len]
outp<-0*0:len2
outp[2] <- yy%*%exp((1:(2*len2))*1.i*pi/len2)
Warning message:
In outp[2] <- yy %*% exp((1:(2 * len2)) * (0+1i) * pi/len2) :
  number of items to replace is not a multiple of replacement length

If you check help("[.xts") you'll notice that drop defaults to FALSE . 如果你检查help("[.xts")你会发现drop默认为FALSE For ordinary matrices the default is TRUE . 对于普通矩阵,默认值为TRUE

str(o_xts[1:len])
# An ‘xts’ object from 2007-01-02 to 2007-06-30 containing:
#   Data: num [1:180, 1] 50 50.2 50.4 50.4 50.2 ...
#  - attr(*, "dimnames")=List of 2
#   ..$ : NULL
#   ..$ : chr "Open"
#   Indexed by objects of class: [POSIXct,POSIXt] TZ: 
#   xts Attributes:  
#  NULL

str(c_xts[1:len])
# num [1:180] 50 50.2 50.4 50.4 50.2 ...

That means that your xx is a 180 element vector whereas your yy is a 180 x 1 matrix. 这意味着你的xx是180元素向量,而你的yy是180 x 1矩阵。 To get the same behaviour in both cases you could use yy <- o_xts[1:len, drop=TRUE] . 要在两种情况下获得相同的行为,您可以使用yy <- o_xts[1:len, drop=TRUE]

I have not (yet) seen any evidence to support the premise of the question, and when I do my own simple test on the first example in help(xts) I come up with contrary evidence: 我还没有看到任何证据支持这个问题的前提,当我在帮助(xts)的第一个例子上做我自己的简单测试时,我得出了相反的证据:

> data(sample_matrix)
> sample.xts <- as.xts(sample_matrix, descr='my new xts object')
> str(coredata(sample.xts))
 num [1:180, 1:4] 50 50.2 50.4 50.4 50.2 ...
 - attr(*, "dimnames")=List of 2
  ..$ : NULL
  ..$ : chr [1:4] "Open" "High" "Low" "Close"
> str(coredata(sample.xts) %*% c(3, 3,3,3) )
 num [1:180, 1] 601 604 604 604 602 ...
> str(sample.xts %*% c(3, 3,3,3) )
 num [1:180, 1] 601 604 604 604 602 ...

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