[英]character array handling in c (copy pointer to character array)
I have a pointer with type const char* FunctionName
, How can I put that into a payload
of type char payload[100]
without any warning or errors? 我有一个类型的指针const char* FunctionName
,我怎样才能将它放入一个payload
类型的char payload[100]
没有任何警告或错误? Also the payload[0]
is filled with character value already, so the space starting from payload[1]
另外, payload[0]
已经用字符值填充,因此从payload[1]
开始的空间
update: 更新:
I tried like this `strcpy((&payload[1]),FunctionName); 我试过这样的`strcpy((&payload [1]),FunctionName); is working now. 现在正在工作。
But Ihave one more question, how can accomodate the pointer(FunctionName) into the payload[1]
ratherthan copying the entire string? 但是我还有一个问题,如何将指针(FunctionName)容纳到payload[1]
不是复制整个字符串? through any assignment statement? 通过任何分配声明?
/R / R
strncpy(&payload[1], FunctionName, 98);
payload[99] = '\0';
should be safe in the case that FunctionName has more than 98 characters before the NULL terminator. 如果FunctionName在NULL终止符之前超过98个字符,则应该是安全的。
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