如何将整数数组的内容复制到字符指针？

Question

I have a character pointer , char *buf; I have a array of integers , int console_buffer[256]; I need to copy the console_buffer contents to character buf. How do I do this? The buf and console_buffer are part of different structures.

Answer 1

Going by your comment,

buf = malloc(256); // 257 if console_buffer may be full without EOF
/* if you want to allocate just as much space as needed, locate the EOF in console_buffer first */
for(int i = 0; i < 256 && console_buffer[i] != -1; ++i){
    buf[i] = (char)console_buffer[i];
}

Answer 2

If you already allocated the memory for buf , and if each integer is between 0 and 9, you can do:

for(int i = 0; i < 256; i++)
{
    buf[i] = '0' + console_buffer[i]; /* convert 1 to '1', etc. */
}

If the integers are larger than 9, you can use the sprintf function.

---

Reading your new comment, perhaps you can also achieve your goal by reading from console buffer directly to an array of chars until you have -1 (check by integers comparison, or by strcmp , or by comparing the 2 last characters to 0 and to 1 ).

Answer 3

I think this is a better way to convert values to char s

int i = 0;
while (i <= 256) {
    buf[i] = (char) console_buffer[i];
    i++;
}