将Map [K，Option [V]]转换为Map [K，V]的更好方法

Question

I have some code that is producing a Map where the values are Option types, and I really of course want a map containing only the real values.

So I need to convert this, and what I've come up with in code is

  def toMap[K,V](input: Map[K, Option[V]]): Map[K, V] = {
    var result: Map[K, V] = Map()
    input.foreach({
      s: Tuple2[K, Option[V]] => {
        s match {
          case (key, Some(value)) => {
            result += ((key, value))
          }
          case _ => {
            // Don't add the None values
          }
        }
      }
    })
    result
  }

which works, but seems inelegant. I suspect there's something for this built into the collections library that I'm missing.

Is there something built in, or a more idiomatic way to accomplish this?

Answer 1

input.collect{case (k, Some(v)) => (k,v)}

Answer 2

input flatMap {case(k,ov) => ov map {v => (k, v)}}

Answer 3

for ((k, Some(v)) <- input) yield (k, v)

从后来的问题来看，这是franza的答案，但值得重新发布。